Answer:
W_net = μ 5.58, μ = 0.1 W_net = 0.558 J
Explanation:
The work is defined by the related
W = F. d = F d cos θ
where bold indicates vectors.
In the case, the work of the friction force on a circular surface is requested.
The expression for the friction force is
fr = μ N
the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1
W = - fr d
the path traveled half the length of the circle
L = 2 π R
d = L / 2
d = π R
we substitute
W = - μ N d
Total work is initial to
W_neto = - μ π R (N_b - N_a)
let's calculate
W_net = - μ π 0.550 (0.670 - 3.90)
W_net = μ 5.58
for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1
W_net = 0.1 5.58
W_net = 0.558 J
Answer:
false
Explanation:
Linear momentum is the product of an objects mass and velocity
p=m×v
Answer:
Option A
20 m/s
Explanation:
From the law of conservation of linear momentum, the sum of momentum before and after collision equals zero hence for this case also, the sum of momentum of the two cars before collision should be equal to momentum after collision.
Momentum is given as the product of mass and velocity, where velocity considers the direction. Momentum, p=mv where m is the mass of the object and v is the velocity.
Momentum before collision
Since the velocities of both cars before collision are zero hence their momentum are zero ie 0.5*0+(1*0)=0
Momentum after collision
For 0.5 Kg car, its momentum will be 0.5*-40=-20 Kg.m/s
For the 1 kg car its momentum will be 1*v=1v
v-20=0
v=20 m/s
C.
The range of temperatures on Earth allows water to exist in all of its states.
