All categories

2 years ago

The temperature of water in a beaker is 45°C. What does this measurement represent

Physics

2 answers:

netineya [11]2 years ago

6 0

Explanation:

Temperature is defined degree of hotness of coldness of a substance.It tells the amount of heat possessed by the particles of the substance.In other words it can also be described as average kinetic energy of the particles of the substance or in the system.

The 45°C represents that the average kinetic energy of the water molecules in the beaker.

andrezito [222]2 years ago

3 0

Based on my information, this would actually be representing "the average kinetic energy of water particles". So, as you take notice that where this temperature is being located, and also, how this would be $45$ °C, this would make more sense for this to be representing as <span>the average kinetic energy of water particles.</span>

You might be interested in

This chart shows characteristics of three different waves all with the same wavelength of 10 m but moving at different frequenci

kap26 [50]

Answer:

the answer is B

Explanation:

wave x has the highest hertz making it the answer

6 0

2 years ago

A parcel of land is in the shape of an isosceles triangle. The base has a length of 425 ft.; the other sides, which are of equal

kogti [31]

Answer:

The answer to your question is 636.6 ft

Explanation:

Data

base = 425 ft

angle = 39°

See the picture below

1.- Divide the triangle to get two right triangles.

Now the superior angle will measure 19.5° and the opposite side will measure 212.5 ft

2.- Use the trigonometric function sine to find the hypotenuse

sin 19.5 = 212.5/hyp

solve for hyp

hyp = 212.5 / sin 19.5

Result

hyp = 212.5/ 0.333

hyp = 636.6 ft

4 0

2 years ago

A car enters a horizontal, curved roadbed of radius 50 m. the coefficient of static friction between the tires and the roadbed i

UkoKoshka [18]

Previous results tell us the speed (v) is given in terms of the coefficient of friction (k) and the radius of the curve (r) as
v = √(kgr)
v = √(0.20·9.8 m/s²·50 m)
= 7√2 m/s ≈ 9.90 m/s

6 0

2 years ago

Read 2 more answers

how much is need to lift a load of 100n placed at a distance of 29 cm from fulcrum if effort is applied at 60cm from the fulcrum

dangina [55]

Answer:

206.8965517 n

Explanation:

First, we need to see that 60:29 is 2.078965517:1. Then we need to multiply the energy put 29 cm from the fulcrum by 2.078965517, giving us the end result of our answer.

6 0

2 years ago

Malcolm and Ravi raced each other. The average of their maximum speeds was 260 km/h If doubled, Malcolm's maximum speed would be

AfilCa [17]

Answer

Given,

Average speed of Malcolm and Ravi = 260 km/h

Let speed of the Malcolm be X and speed of the Ravi Y.

From the given statement

$\dfrac{X+Y}{2}=260$

$X + Y = 520$ ....(i)

$2X - Y = 80$ ....(ii)

Adding both the equations

3 X = 600

X = 200 km/h

Putting value in equation (i)

Y = 520 - 200

Y = 320 Km/h

Speed of Malcolm = 200 Km/h

Speed of Ravi = 320 Km/h

8 0

2 years ago