Answer:
v₀₂ = -2.67 m / s
Explanation:
Let's use the conservation of the moment, for this we define a system formed by the two cars.
Consider the north direction as positive and the subscript 1 will be used for car 1 and the subscript 2 for the second car
Initial instant. Before the crash
p₀ = -m₁ v₀₁ + m₂ v₀₂
Final moment. Right after the crash
p_f = (m₁ + m₂) v
p₀ = p_f
-m₁ 
+ m₂ v_{o2} = (m₁ + m2) v_{f}
v₀₂ = 
+ 
let's calculate
v₀₂ = 
v₀₂ = -2.67 m / s
the negative sign indicates that the carriage moves in the opposite direction of the temperies
Answer: Input Resistance (Rin) = 500 ohms , overall voltage Gain (GV) = 2 volts / volts , ID = 4/9 = 0.44 A
Explanation:
KE= (1/2) mv²
So, the variables we need to include in our question would be a varable for a mass(m) of an object at some velocity(v).
My Answer:
(This is just an example question, yours can be different)
What is the Kinetic Energy experienced by an bouncy ball rolling at 7m/s (that's your velocity) across a frictionless surface that has a mass(m) of 10 grams?
Answer:
W = 7056 J
Explanation:
Given that,
Mass of a load, m = 60 kg
Distance moved, d = 12 m
We need to find the amount of work. The work done by an object is given by :
W = Fd
So,
W = mg×d
W = 60 kg × 9.8 m/s²×12 m
W = 7056 J
So, the amount of work done is 7056 J.
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