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3 years ago

How longitudinal waves are formed

Physics

2 answers:

vfiekz [6]3 years ago

6 0

Answer:

forever

Explanation:

Vladimir79 [104]3 years ago

3 0

Air molecules move in a direction that is parallel to the direction that the wave moves, the sound waves is referred as a longitudinal wave .

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A ball is kicked horizontally from a 60 meter tall cliff at 10 m/s. How far from

o-na [289]

Hi there!

We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.

$\large\boxed{\Delta d = v_it+ \frac{1}{2}at^2}}$

There is NO initial vertical velocity, so:

$\large\boxed{\Delta d= \frac{1}{2}at^2}}$

Rearrange to solve for time:

$2\Delta d = at^2\\\\t = \sqrt{\frac{2\Delta d}{g}}$

Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)

$t = \sqrt{\frac{2(60)}{(9.8)}} = 3.5 s$

Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:

$\large\boxed{d_x = vt}\\\\d_x = 10(3.5) = \karge\boxed{35 m}$

6 0

3 years ago

Find the force on an object which has the mass of 20kg and an acceleration of 10m/s

Elis [28]

Answer:

200 Newtons

Explanation:

20 kg x 10 m/s squared

4 0

3 years ago

If a magnet is broken into two pieces, what happens to the magnetic poles?

Nostrana [21]

Answer:

The second is correct.

Explanation:

Try with a magnet and experiment. You'll find out

6 0

3 years ago

Read 2 more answers

One strategy in a snowball at a high angle over level ground. While your opponent is watching this first snowball, you throw a s

siniylev [52]

Answer:

33°

Explanation:

We are given;

Speed at which both snowballs are thrown; v = 33.2 m/s

Angle at which snowballs are thrown with respect to the horizontal; θ = 57°

Now,we want to find out the angle at which the second snowball should be thrown in order to arrive at the same point as the first.

To calculate this angle, we will use complementary angle concept.

Now, because the target is in the same place, there will be two launch angles that will make the snow ball to be placed on the target.

The is calculated from;θ1 = 45° - (57° - 45°) = 33°

8 0

3 years ago

There is a small scratch on a disco record located 14.5 cm from the center. When played, the scratch makes the record skip 30 ti

LuckyWell [14K]

Answer:

The linear speed of scratch is 45.55 cm/dec

Explanation:

The scratch located from the center at radial distance = 14.5 cm.

Each minute the skip of scratch when disco record played = 30 times

Since, the scratch on the disc start revolving when disc is played and in one minute the scratch revolve 30 times. Therefore, the revolution = 30 RPM

Below is the calculation of linear speed of the scratch.

$Angular \ velocity, \ w \ = \frac{2 \pi \times RPM}{60} \\$

$w = \frac{2 \pi \times 30}{60} = \pi \ rad/dec \\$

$Linear \ velocity = wr \\$

$r = radial \ distance \\$

$v = \pi \times 14.5 \\$

$v = 45.55 cm/dec$

3 0

3 years ago