The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V
<u>Explanation:</u>
Given data,
E= 3 ×10 ⁶ Δx=0.06/100
We have to find the minimum potential difference
E= -ΔV/Δx
ΔV=- E × Δx
ΔV =-3 ×10 ⁶ . 0.06/100
ΔV=-1800 V
The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V
Answer:
Hydrated iron(III) oxide, or ferric oxide
Explanation:
B.) <span>The range of all electromagnetic radiation is known as the "Electromagnetic Spectrum"
Hope this helps!
</span>
It is trajectory acceleration. A friction track is a device to study motion in low friction environments, I believe. Does this help?
