The electric current passing through the bulb would be 3.3A
<u>Explanation:</u>
Given:
Electric charge, q = 800C
Time, t = 4 min
= 4 X 60 sec
= 240 sec
Electric current, I = ?
We know,
On substituting the value we get:
Thus, the electric current passing through the bulb would be 3.3A
Answer: 2.5 m/s and 6.25 m
Explanation:
u = 0
a = 0.5 m/s²
t = 5 s
v = u + at
= 0 + 0.5 × 5
= <u>2.5 m/s</u>
s = ut + 1/2 at²
= 1/2 × 2.5 × 5
=<u> 6.25 m</u>
A=Fh
A - work
F - force
h - distance
F=mg
m - mass (god+basket)
so
A=mgh
187 = m*10*4
187=40m
m=187/40
m=4.675 kg
or 4kg and 675g
pretty small dog...
Answer:
variables on the horizontal and vertical axis (slope, outliers, +/- correlation, etc)
Explanation: