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Liono4ka [1.6K]
4 years ago
13

Add.

Mathematics
1 answer:
Temka [501]4 years ago
4 0
0.13888888888 is the answer hope it helps
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the population of a school is 400 students. Next year it is expected to be about 120% of what it is now. Choose next year's stud
Gelneren [198K]
Given:
this year's population: 400 students
next year's population: 120% of this year's population

this year's population x rate of next year's population = next year's population

400 students * 120% = 480 students  CHOICE D.

There will be 480 students next year.


5 0
3 years ago
Solve for x: 1 1/5 x -2 1/3 < 1/7 x+ 1 1/2
Firlakuza [10]
Solving inequalities is similar to solving a regular equation. The only thing you need to worry about with inequalities is that when you are dividing or multiplying by a negative number, you must flip the inequality sign. You won't have to worry about that here if the coefficient in front of x is positive when you divide!

Also remember:
- To add/subtract fractions, you have to turn all mixed numbers into improper fractions (if needed), <span>find a common denominator on both fractions (if needed), add/subtract the numerators, put the sum/difference over the common denominator, and simplify if needed. 

- To multiply fractions, multiply the numerators and multiply the denominators. Put the product of the numerators over the product of the denominators.

- To divide fractions, remember that dividing by a fraction is the same as multiplying by the inverse of that fraction (aka fraction flipped). 

- To turn mixed numbers into improper fractions, multiply the whole number by the denominator of the fraction. Add the numerator of the fraction to the product you get, and put that final sum over the original denominator.

Back to the problem:
</span>You are told that 1 \frac{1}{5} x - 2 \frac{1}{3} \ \textless \ \frac{1}{7} x + 1 \frac{1}{2} and you have to solve for x.
<span>
1) </span>Using the info for converting mixed numbers to improper fractions from above, you know that 1 \frac{1}{2} =  \frac{3}{2} and 2 \frac{1}{3} =  \frac{7}{3} and 1 \frac{1}{5} x =  \frac{6}{5} x. Now add/subtract using the info above, isolating the variable x by adding 2 \frac{1}{3} to both sides and subtracting \frac{1}{7} x from both sides. 
1 \frac{1}{5} x - 2 \frac{1}{3} \ \textless \ \frac{1}{7} x + 1 \frac{1}{2}\\&#10;\frac{6}{5} x -  \frac{7}{3} \ \textless \ \frac{1}{7} x + \frac{3}{2}\\&#10;(\frac{6}{5} x  - \frac{1}{7} x) \ \textless \ (\frac{3}{2} + \frac{7}{3})\\&#10;(\frac{42}{35} x  - \frac{5}{35} x) \ \textless \ (\frac{9}{6} + \frac{14}{6})\\&#10; \frac{37}{35} x \ \textless \   \frac{23}{6}

2) Divide both sides by \frac{37}{35} to get the inequality for x. Remember the info for dividing from above:
\frac{37}{35} x \ \textless \ \frac{23}{6}\\&#10;x \ \textless \  \frac{23}{6} \div \frac{37}{35}  \\&#10;x \ \textless \  \frac{23}{6} \times \frac{35}{37} \\&#10;x \ \textless \  \frac{805}{222}

Your final answer is x < \frac{805}{222} or x < 3 \frac{139}{222}.
3 0
4 years ago
Math problem help me
Ratling [72]

Answer:

y=3x+2

Step-by-step explanation:

To find the equation, use the slope-intercept formula:

y=mx+b

m is the slope and b is the y-intercept. Now, it'll really help to draw a line through the points, connecting them. If you look at point (0,2), we can see that this is the y-intercept (where a point sits on the y-axis when x=0). You can insert this into the equation by taking the y value:

(0,2)\\y=mx+2

Now, take any two points to find the slope. To make it easier, I'll use (1,5) and (0,2). Use the slope formula for when you know two points:

\frac{y(2)-y(1)}{x(2)-(x1)} =\frac{rise}{run}

Rise over run is the change in the y-axis over the change in the x-axis. Insert values:

(1(x1),5(y1))\\(0(x2),2(y2))\\\\\frac{2-5}{0-1}

Solve:

\frac{2-5}{0-1}=\frac{-3}{-1}

Since both are negative, the result is a positive:

\frac{-3}{-1}=\frac{3}{1} =3

Insert this into the equation as m, the slope:

y=3x+2

Done.

6 0
3 years ago
Which rules of exponents will be used to evaluate this expression? Check all that apply. StartFraction left-brace (negative 8) S
ExtremeBDS [4]
Answer:
X product of powers
Quotient of powers
Power of a power
X power of a product
Negative exponent
X zero exponent

Hope this helps ʕ•ᴥ•ʔ
5 0
3 years ago
HELP PLZ !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Yakvenalex [24]

Answer:

B. BC ≅ LM

Step-by-step explanation:

BC corresponds to LM. These are the only two sides without the hash marks that represent congruence. If the marks were there to indicate that the sides are congruent, then the triangles could be proved congruent by SSS.

5 0
3 years ago
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