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muminat
3 years ago
15

An element's atomic number is 86. how many protons would an atom of this element have?

Chemistry
1 answer:
rusak2 [61]3 years ago
8 0
The number of protons an element has is the same as the atomic number, so the element would have 86 protons.
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The molar volume of a gas at STP occupies <u>22.4 L.</u>

Option D

<u>Explanation:</u>

To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,

P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)

STP = 1 atm of pressure and 273 K for temperature

P = 1 atm

V = ?

n = 1 mole

R = 0.0821 atm L/mol K

T = 273 K

Using the equation,

\mathrm{PV}=\mathrm{nRT}

V=\frac{n R T}{P}

By substituting the above values, in the equation,

V=\frac{1 \times 0.082 \times 273}{1}=22.38\ L

V = 22.38 L

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3 years ago
Lithium Iodide Has A Lattice Energy Of −7.3×102kJ/mol And A Heat Of Hydration Of −793kJ/mol. Lithium iodide has a lattice energy
daser333 [38]

Answer:

Heat of solution= - 63KJ/mole

Heat evolved = - 18.82KJ

Explanation:Heat of solution = Heat of solute + Heat of hydration

◇Hsoln = - ( - 7.3 × 10 ^ 2) + ( - 793 ) KJ / mol

◇H soln= - 63 KJ

Use enthalpy of solution equation to determine the enthalpy of solution for LiI

LiI ---> Li^ + + I^-

Molecular mass of LiI=133.85g

The chemical equation for the dissociation will be:

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18.82KJ

The heat was evolved because the value of enthalpy was negative

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4 years ago
A bicycle tire has a volume of 1.0 l at 22°c. if the temperature of the tire is increased to 52°c, what is the resulting volume
tresset_1 [31]

The relationship between the volume, temperature, and pressure of the gas can be given by Charles law. The volume of the tire is 1.1 L.

<h3>What is Charle's law?</h3>

According to Charles's law, the volume is directly proportional to the temperature of the gas at a constant pressure.

Charle's law can be shown as,

\rm \dfrac{V_{1}}{T_{1}} = \rm \dfrac{V_{2}}{T_{2}}

Given,

Initial volume = 1.0 L

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Substituting values in the above equation the final volume can be calculated as:

\begin{aligned}\rm V_{2} &= \rm \dfrac{V_{1}T_{2}}{T_{1}}\\\\&= \dfrac{ 1 \times 325}{295}\\\\&= 1.1\;\rm L\end{aligned}

Therefore, the final resulting volume of the tire is 1.1 L.

Learn more about Charle's law here:

brainly.com/question/26849359

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