The molarity of the diluted solution is 0.33 M
From the question given above, the following data were obtained:
Molarity of stock solution (M₁) = 0. 5 M
Volume of stock solution (V₁) = 100 mL
Volume of diluted solution (V₂) = 100 + 50 = 150 mL
<h3>Molarity of diluted solution (M₂) =? </h3>
The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:
<h3>M₁V₁ = M₂V₂</h3>
0.5 × 100 = M₂ × 150
50 = M₂ × 150
Divide both side by 150
M₂ = 50 / 150
<h3>M₂ = 0.33 M</h3>
Therefore, the molarity of the diluted solution is 0.33 M
Learn more: brainly.com/question/24625656
The mass of 5.2 x 10^22 manganese atoms in grams would be 635.784 grams.
What is Avogadro's constant?
Avogadro's number tells us how many particles are in one mole (or mol) of a substance. <u>Electrons</u><u>, molecules, or atoms</u> could be among these particles. Avogadro's number has a value of approximately 6.022140857×10²³ mol⁻¹. Avogadro's number tells us how many particles are in one mole (or mol) of a substance. <u>Electrons, molecules, or atoms </u>could be among these particles. Avogadro's number has a value of approximately 6.022140857×10²³.
Computation of mass
Avogadro calculated that every material had 6.022 x 10^23 atoms per mole.
5.2 x 10^22 atoms of Mn would contain how many moles?
= 6.022 x 10^23 /1 x 5.2 x10^22
=11.58 moles
Mn mass equals 11.58 moles multiplied by 54.9
= 635.784 grams
You may learn more about Avogadro's constant here: brainly.com/question/15989275
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Answer:
Explanation:
Entropy is the degree of randomness or disorderliness of as system. The more random a system tends, the more positive the entropy. Gases have the highest entropy whereas solids have little to no entropy.
When a reaction goes from one initally with a lower entropy to one with a higher entropy, the change in entropy, ΔS is postive. ΔS is negative when a reaction goes from one with a higher entropy to one with lower entropy.
When there is no entropy change, both the reactants and products are in the same state.
In the first reaction, UF₆ is in a gaseous phase and it was seperated into two gaseous products, 238-UF₆ and 235-UF₆. Therefore, ΔS is zero i.e no change in entropy of the system.
In the second reaction, solid I₂ is dissolved in CCl₄. The solid substance goes into solution to form a liquid medium. This is an increase in the randomness or entropy of the system. Therefore ΔS is +ve.
To find the density, the formula would be d= m/V. Your answer would be 19.9 or if you round, 20.
<u>Answer:</u> The concentration of solute is 0.503 mol/L
<u>Explanation:</u>
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
where,
= osmotic pressure of the solution = 24 atm
i = Van't hoff factor = 2 (for NaCl)
c = concentration of solute = ?
R = Gas constant = 
T = temperature of the solution = ![25^oC=[273+25]=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B273%2B25%5D%3D298K)
Putting values in above equation, we get:
Hence, the concentration of solute is 0.503 mol/L
