The molarity of a Ba(OH)2 solution required to prepare a1.0 OH- solution is calculated as follows
write the equation for dissociation of Ba(Oh)2
that is,
Ba(Oh)2 -----> Ba^2+ + 2Oh-
by use of reacting ratio between Ba(Oh)2 to Oh which is 1:2 the molarity of Ba(oh)2 = 1.0/2 = 0.5 M
<span>Read the Fig 4 description. From there you can conclude that it does scatter light, because its ot a solution. So it must be a mixture, the substances are not dissolved so therfore they aren't a solution.</span>
Given:
rate = k [A]2
concentration is
0.10 moles/liter
rate is 2.7 × 10-5 M*s-1
Required:
Value of k
Solution:
rate = k [A]2
2.7 × 10-5 M*s-1
= k (0.10 moles/liter)^2
k = 2.7 x 10^-3
liter per mole per second
Answer:
See explanation below
Explanation:
First to all, you need to know what is the function of NBS.
N-Bromosuccinimide (NBS) is a brominating and oxidizing agent that is used as source for bromine in radical reactions (for example: allylic brominations) and various electrophilic additions.
In this case, when it's present the light or heat, this agent acts as electrophylic addition, so, instead of going to the double bond, it's going to do an allylic bromination, so the possible products are the following: (See picture)
Answer:
Explanation:
If an electron is in an excited state it can return to a lower energy level. When it does this, it loses energy. The amount of energy it loses will be equal to the difference in the energy levels it moves between. This energy is released as a photon.
