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Mumz [18]
2 years ago
13

Arrange the following ions in order of increasing ionic radius.

Chemistry
1 answer:
Zepler [3.9K]2 years ago
3 0

Answer:

Ca 2+ <K  +  <Ar<Cl  −  <S  2−

Explanation:

Ar,K  + ,Cl  − ,S  2− ,Ca  2+

 have the same number of electrons. Their radii would be different because of their different nuclear charges. The cation with the greater positive charge will have a smaller radius because of the greater attraction of the electrons to the nucleus. Anion with the greater negative charge will have the larger radius. In this case, the net repulsion of the electrons will outweigh the nuclear charge and the ion will expand in size. Hence the correct order will be Ca  

2+  <K +  <Ar<Cl  −  <S  2−

 

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Which of the following is true of solids?
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<span>Answer: B. Ionic solids have higher melting points than molecular solids.
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This is because the rest are false, as solids are able to melt, and do have melting points. Also, not all solids have the same melting points. 
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2 years ago
Acid rain water breaks down Rocks by_____ weathering​
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3 years ago
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Ganezh [65]

Answer:

1 Atm

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Dalton's law

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4 0
3 years ago
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If a bus traveled 20 miles north on a straight path, and then traveled 20 miles back to the starting point, what would the veloc
AleksAgata [21]

<u>Answer:</u>

The velocity of the bus be is 0 miles/second

<u>Explanation:</u>

Given, a bus travelled a distance of 20 miles north and 20 miles back to the starting point

Hence, total distance = 20 + 20 = 40 miles

Velocity is calculated by the formula:

Velocity =   \frac{\text { Displacement }}{\text { Time }}

Displacement = 20+(-20)=0 \text { miles }

Velocity = \frac{0}{T i m e}=0 \text { miles/second }

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5 0
3 years ago
54.56 g of water at 80.4 oC is added to a calorimeter that contains 47.24 g of water at 40 oC. If the final temperature of the s
fomenos

Answer:

49.5J/°C

Explanation:

The hot water lost some energy that is gained for cold water and the calorimeter.

The equation is:

Q(Hot water) = Q(Cold water) + Q(Calorimeter)

<em>Where:</em>

Q(Hot water) = S*m*ΔT = 4.184J/g°C*54.56g*(80.4°C-59.4°C) = 4794J

Q(Cold water) = S*m*ΔT = 4.184J/g°C*47.24g*(59.4°C-40°C) = 3834J

That means the heat gained by the calorimeter is

Q(Calorimeter) = 4794J - 3834J = 960J

The calorimeter constant is the heat gained per °C. The change in temperature of the calorimeter is:

59.4°C-40°C = 19.4°C

And calorimeter constant is:

960J/19.4°C =

<h3>49.5J/°C</h3>

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7 0
2 years ago
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