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anzhelika [568]
2 years ago
15

Methane (CH4) is a gas that is found in small quantities in earths atmosphere. which type of bonds does methane have and why doe

s one carbon Atom bond with four hydrogen Atoms? in 3 to 5 sentences explain your answer in terms of valence electrons and electronegativity.
Chemistry
1 answer:
OLga [1]2 years ago
8 0

Answer:

Methane is a covalent bond. Methane is a chemical compound from the bonding  one carbon atom and for hydrogen atoms. Although electronegativity increases as you go right of the periodic table, hydrogen has an electronegativity of 2.20. Chlorine has an electronegativity of 2.55. There difference in electron negativity (0.34). Therefore it is a non polar compound. If there difference was much greater, than they would form a ionic bond. Alkali metals tend to form the most ionic bond, but although hyrdogen is placed with them, it has a higher electronegativity so hydrogen is an exception.

Carbon has 4 valence electrons so it will want to gain 4 more electrons to become stable (Octet rule). Hydrogen has 1 valence electron, so it will want to lose it to become stable. Therefore, one carbon atom takes 1 electrons from 4 hydrogen atoms.

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A 300-gallon anaerobic digester will be loaded daily with a feedstock that contains two parts dairy manure and one-part water by
Mars2501 [29]

Answer:

The volume of feedstock needed to mantain an organic load rate of 2 kgVS/day is 0.055 m3/day of feedstock.

The HRT is 20.6 days.

Explanation:

First, we calculate how many kg is 1 m3 of feedstock. We know the density, so we can calculate the mass:

M=\rho*V=37.5\frac{lb}{ft^3}*1m^3*(\frac{3.281ft}{1m})  ^3=1324.5lb=600.7 kg

If the VS are 6% in weight,

M_{vs}=0.06*M=0.06*600.7\,kg/m^3=36,0kgVS/m3

The volume per day needed to feed 2 kg of VS/day is:

V=\frac{2kg}{36kg/m^3}= 0.055m3/day=5.5litres/day

The HRT depends on the volume of the tank and the flow. Its equation is

HRT=\frac{V}{Q}=\frac{300gal}{0.055 m^3/day}*\frac{1m^3}{264.172gal}\\   \\HRT=20.6\,days

6 0
3 years ago
Could anyone help me with question 3?
Gwar [14]
Second one i think.......
3 0
3 years ago
Draw a Lewis structure for SO2 in which all atoms have a formal charge of zero. Explicitly showing the zero charges is optional.
Radda [10]

Answer:

See explanation and image attached

Explanation:

"A formal charge (FC) is the charge assigned to an atom in a molecule, assuming that electrons in all chemical bonds are shared equally between atoms, regardless of relative electronegativity" (chemlibretext).

We can obtain the formal charge from the formula;

Formal Charge = [number of valence electrons on atom] – [non-bonded electrons + 1/2number of bonds].

A structure in which SO2 has a zero formal charge is attached to this answer.

Image credit: Chemtopper

3 0
3 years ago
PLSSS HELP I AM STUCK ON THIS PROBLEM!!!
DENIUS [597]

Answer:

i can't read it.. maybe upload a visible picture?

6 0
3 years ago
A 1.30M solution of BaCl2 has a density of 1.230 g/ml. a) What is the mole fraction of BaCl2 in this solution?
Elodia [21]

<u>Answer:</u> The mole fraction of barium chloride in the solution is 0.024

<u>Explanation:</u>

We are given:

Molarity of barium chloride solution = 1.30 M

This means that 1.30 moles of barium chloride is present in 1 L or 1000 mL of solution.

  • To calculate the mass of solution, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.230 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

1.230g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.230g/mL\times 1000mL)=1230g

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Moles of barium chloride = 1.30 moles

Molar mass of barium chloride = 208 g/mol

Putting values in equation 1, we get:

1.30mol=\frac{\text{Mass of barium chloride}}{208g/mol}\\\\\text{Mass of barium chloride}=(1.30mol\times 208g/mol)=270.4g

Mass of water = Mass of solution - Mass of barium chloride

Mass of water = 1230 - 270.4 = 959.6 g

<u>Calculating the moles of water:</u>

Given mass of water = 959.6 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{959.6g}{18g/mol}\\\\\text{Moles of water}=53.31mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

  • <u>For barium chloride:</u>

\chi_{\text{(barium chloride)}}=\frac{n_{\text{(barium chloride)}}}{n_{\text{(water)}}+n_{\text{(barium chloride)}}}

\chi_{\text{(barium chloride)}}=\frac{1.30}{1.30+53.31}\\\\\chi_{\text{(barium chloride)}}=0.024

Hence, the mole fraction of barium chloride in the solution is 0.024

6 0
4 years ago
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