Methane (CH4) is a gas that is found in small quantities in earths atmosphere. which type of bonds does methane have and why doe
1 answer:
Answer:
Methane is a covalent bond. Methane is a chemical compound from the bonding one carbon atom and for hydrogen atoms. Although electronegativity increases as you go right of the periodic table, hydrogen has an electronegativity of 2.20. Chlorine has an electronegativity of 2.55. There difference in electron negativity (0.34). Therefore it is a non polar compound. If there difference was much greater, than they would form a ionic bond. Alkali metals tend to form the most ionic bond, but although hyrdogen is placed with them, it has a higher electronegativity so hydrogen is an exception.
Carbon has 4 valence electrons so it will want to gain 4 more electrons to become stable (Octet rule). Hydrogen has 1 valence electron, so it will want to lose it to become stable. Therefore, one carbon atom takes 1 electrons from 4 hydrogen atoms.
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Answer : The correct answer is the Bonds were broken on the reactants and new bonds were formed on the products.
Explanation :
In the chemical reaction, some substances react together are called reactant and the substance are formed are called product.
During the chemical reaction, the atoms of reactants rearranged to make products. There are on atoms are added or taken away in the reaction. This is known as the conservation of atoms.
For example : carbon atom react with the oxygen to form carbon dioxide.
From the given diagram, we conclude that the arrangement of molecules are different on both side of the mixture of reaction.
On the reactant side, the red molecules bonded with red molecule and the black molecule with white molecules. On the other hand i.e product side, the red molecule bonded with black molecule and white molecule bonded with red molecules. The molecular arrangement are different on both side of the reaction mixture.
Therefore, the correct answer is the Bonds were broken on the reactants and new bonds were formed on the products.