Answer:

Step-by-step explanation:
Given



Required
The volume of the remaining cylinder
Before the cut-out, the cylinder has a volume (V) of:

After the cut-out, the cylinder has a volume of:
![V = \pi [R^2 -r^2]h](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20%5BR%5E2%20-r%5E2%5Dh)
So, we have:
![V = 3.14* [6^2 -5^2]*15](https://tex.z-dn.net/?f=V%20%3D%203.14%2A%20%5B6%5E2%20-5%5E2%5D%2A15)
![V = 3.14* [36 -25]*15](https://tex.z-dn.net/?f=V%20%3D%203.14%2A%20%5B36%20-25%5D%2A15)


Answer:
C.
Step-by-step explanation:
(∛5)^7
= (5 ^ 1/3)^7
= 5^(7/3)
Well u have to make the denominator the same so u multiply 3/8 by 3 and get 9/24, then multiple 2/6 by three and get 8/24. Add them, 9/24+8/24 and u get 17/24