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3 years ago

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What is the area of a sector with a central angle of 2π9 radians and a radius of 16. 7 ft? Use 3. 14 for π and round your final

answer to the nearest hundredth. Enter your answer as a decimal in the box. Ft².

1 answer:

Bas_tet [7]3 years ago

6 0

gehhehehhehdjejuriruueue

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Two of the most popular options on a certain type of new car are automatic transmission and built-in GPS. Suppose that 90% of al

padilas [110]

Answer:

0.95 = 95% probability that the next person to purchase this car will request at least one of automatic transmission or built-in GPS

Step-by-step explanation:

We solve this question treating these probabilities as Venn sets.

I am going to say that:

Event A: Requesting automatic transmission

Event B: Requesting built-in GPS

90% of all buyers request automatic transmission

This means that $P(A) = 0.9$

82% of all buyers request built-in GPS

This means that $P(B) = 0.82$

77% of all buyers request both automatic transmission and built-in GPS.

This means that $P(A \cap B) = 0.77$

What is the probability that the next person to purchase this car will request at least one of automatic transmission or built-in GPS

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

So

$P(A \cup B) = 0.9 + 0.82 - 0.77 = 0.95$

0.95 = 95% probability that the next person to purchase this car will request at least one of automatic transmission or built-in GPS

3 0

3 years ago

So, which one is the answer?

Flauer [41]

2272in^3 because volume is always measured in ^3

6 0

3 years ago

Read 2 more answers

Use the drop-down menus to choose steps in order to correctly solve 3+4d−14=15−5d−4d for d.

Kisachek [45]

Answer:

d=2

Step-by-step explanation:

SHOWN BELOW

8 0

3 years ago

Read 2 more answers

I really need a answer ASAP

Elza [17]

Answer:

e and c

Step-by-step explanation:

4 0

3 years ago

Anastaziya [24]

That'd be true only if the value of "s" is the exact same one for both
namely if sec(s) = cos(s)
then solving for "s"
thus

$\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)}
\\\\\\
thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s)
\\\\\\
\pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides}
\\\\\\
cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s$

5 0

3 years ago