Answer:
it would be 5,045
Explanation:
because it is closer to 5,000. pls correct me if wrong
Before you can identify how much you need, first you need to
solve and write the equation.
You need to know first that you need to convert grams of ZnO --> moles of ZnO
= 358.5 g ZnO x 1 mol ZnO / 81.39g ZnO
Solve and it will give you = 4.40 mol of ZnO
Next, multiply the answer above to 1 mol O2 / 2 mol ZnO
It will give you the answer of 2.20 mol of O2
Multiply the answer above to the molar mass. This will give
you the answer of what you’re looking for.
Molar mass: 32
= 2.20 mol O2 x 32g O2 / 1 mol O2
= 70.4g O2
The grams of O2 that are required to produce 385.5 grams of
zno is: 70.4 g O2
Answer:
There are more nutrients available in estuaries. There are more nutrients available in estuaries.
Explanation:
Answer:
The correct option is: b. has a downward projection (on the opposite side from the terminal CH₂OH group).
Explanation:
The Haworth Projection depicts the three-dimensional cyclic structure of the monosaccharides.
The monosaccharide, D-glucose predominantly exists in the pyranose form and is known as D-glucopyranose. The D-glucopyranose has two anomeric forms: α- and the β- form and the carbon-1 (C-1 ) is known as the anomeric carbon.
<u>In the Haworth projection of α-D-glucopyranose</u>, the <u>hydroxyl group of anomeric carbon is projected in the downward direction</u>. Whereas, the <u>terminal CH₂OH group on the carbon-5 (C-5), is projected in the upward direction.</u> Therefore, they are on the <u>opposite sides of the plane of ring</u>.