Answer: Compounds that contain a carbon-carbon double bond are known as _____alkenes_______ . Alkenes are electron rich; therefore, simple alkenes do not react with _____nuceophiles_______ or bases, but will react with _____electrophiles_______ or acids. In the IUPAC system, an alkene is identified by the suffix _____-ene_______ . Addition reactions in which two parts of a reagent are added to the same side of a double bond are known as _____syn_______ additions. Addition reactions in which two parts of a reagent are added from opposite sides of a double bond are called _____anti_______ additions. Halogenation and halohydrin formation occur with _____anti_______ addition. Hydroboration occurs with _____syn_______ addition.
Explanation:
The right terms have been filled into the statement.
Electrophiles are election rich so they react with nucleophiles. And vice versa.
Addition reactions in which two parts of a reagent are added to the same side of a double bond are known as _syn reaction and that involving opposite is anti reaction.
The Halohydrin formation reaction involves breaking a pi bond and creating a halohydrin in its place. Halo = halogen and Hydrin = OH. This reaction takes place in water and yields an anti-addition reaction which follows Markovnikov's rule.
Answer:
Humans have impacted the hydrosphere drastically and will only continue to due so based on population needs. Global climate change, water pollution, damming of rivers, wetland drainage, reduction in stream flow, and irrigation have all exerted pressure on the hydrosphere's existing freshwater systems.
Hope it helps :)
Unit of M is also mole/L, where mole is the moles of solute and L is the volume of the solution. The latter is given: 158 mL or 0.158 L. So we need to find out the moles of NH4Br.
Moles of NH4Br = Mass of NH4Br/molar mass of NH4Br = 17.0g/(14+1*4+79.9)g/mol = 0.1736 mole.
So, the molarity of the solution = 0.1736mole/0.158L = 1.10 mole/L = 1.10 M
No, because the sun stays in the same exact place all of the time
