All categories

4 years ago

Write a polynomial function in standard form with zeros at -7, 0, and 1

Mathematics

1 answer:

Semmy [17]4 years ago

7 0

Answer:

C. $x^3+6x^2-7x$

Step-by-step explanation:

The zeros of a polynomial are the solutions to the function. They are found from the factors. The factors which multiply to make the equation in standard form. To write the factors reverse the process by unsolving the factor.

x = -7 comes from x+7

x = 0 comes from x

x = 1 comes from x-1

The factored form is x(x+7)(x-1). Find the factored form by multiplying.

$x(x+7)(x-1)\\(x^2+7x)(x-1)\\x^3+7x^2-x^2-7x\\x^3+6x^2-7x$

You might be interested in

3(x-8) = -29.7 please solve for x

GrogVix [38]

Answer:

The answer is x= -1.9.

Use the 3 to multiply the number and the letter in the bracket... which is...

3x-24=-29.7.

3x=-29.7+24.

3x=-5.7.

x=-5.7/3.

x=-1.9.

6 0

3 years ago

On the graph shown, what is f(-1)? (5 points) The first segment joints the point negative three comma five exclusively and negat

tatiyna

ANSWER

$f( - 1) = 2$

EXPLANATION

The given function is a piecewise defined function.

$f( - 1)$
is the y-value that corresponds to
$x = - 1.$

To determine that y-value, we need to trace from
$x = - 1$
to where it meets the graph.

We then trace to the y-axis to determine the corresponding y-value as shown in the diagram.

From the graph, we can see that this x-value corresponds to a y-value of
$2$

This implies that, when
$x = - 1,y = 2$

Therefore
$f( - 1) = 2$
See graph.

8 0

3 years ago

Find the equation of the line that passes through (1,3) and is perpendicular to y = 1 − 2 x

egoroff_w [7]

Answer:

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept.

Perpendicular lines always have slopes that are negative reciprocals (ex. 1/2 and -2, 3/4 and -4/3)

Determine the slope (m):

$y = 1 -2x$

Rearrange into slope-intercept form:

$y = -2x+1$

Now, we can identify clearly that the slope is -2. Because perpendicular lines always have slopes that are negative reciprocals, a perpendicular line would have a slope of $\displaystyle\frac{1}{2}$ . Plug this into $y=mx+b$ :