Answer:
Step-by-step explanation:
To simplify recall exponent rules:
1. An exponent is only a short cut for multiplication. It simplifies how we write the expression.
2. When we multiply terms with the same bases, we add exponents.
3. When we divide terms with the same bases, we subtract exponents.
4. When we have a base to the exponent of 0, it is 1.
5. A negative exponent creates a fraction.
6. When we raise an exponent to an exponent, we multiply exponents.
7. When we have exponents with parenthesis, we apply it to everything in the parenthesis.
We will use these rules to simplify.
Use rule #3 to simplify inside the parenthesis first.
Now simplify the exponent of 4 using rule 6.
Sorry that is wrong, you distribute the 2 to the h and the 8 so it would be 2h-16-h. that would be h-16 on the left side,
Her credits need to be AT LEAST EQUAL TO OR GREATER THAN 144 (credit hours) so we can eliminate choices B and D.
She already completed 4 semesters in which she receives 15 credit per semester.
This expression can be written as 4(15).
She needs to do a certain remaining hours of credit which can be represented by c and only c without any other coefficient.
So, the most reasonable choice here is A.
A nickel is worth 5 cents. So if he has 5 nickels extra. They are worth 25 cents. Subtract 0.25 from 4.35 and you get 4.10. Now all you have to do is divide 4.10 by 0.05, which is a nickel. The answer is "Mike thought he had 82 nickels"
Answer:
True, false, true, true.
Step-by-step explanation:
The roots zeros of a quadratic function are the same as the factors of the quadratic function. This is true because your roots are your factors—>(x-3) is a factor, x=3 is the root.
The roots zeros are the spots where the quadratic function intersects with the y-axis. No! Those are called y-intercepts!
The roots zeros are the spots where the quadratic function intersects with the x-axis. True. X-intercepts are your solutions. (x-3) graphed would the (3,0). That’s a solution.
There are not always two roots/zeros of a quadratic function, True. No solution would be when your quadratic doesn’t intersect the x-axis. One solution would be when your vertex would be on the x-axis. Two solutions is when your quadratic intersects the x-axis twice. Can there be infinite solutions? No. It’s either 0, 1, or 2 solutions.
