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3 years ago

Which of the following compounds has the largest formula mass? H20 NH3 со BeH2

Chemistry

1 answer:

WINSTONCH [101]3 years ago

3 0

CO has the largest formula mass.

<h3><u>Explanation:</u></h3>

The formula mass of carbon monoxide, CO.

The relative atomic mass of carbon is 12 and of oxygen is 16, so the relative formula mass is: 12 + 16 = 28

The formula mass of $H_2O$ :

$\frac{(2\ H\ atoms) 1.01\ amu}{ 1\ H\ atom}$ = 2.02 amu (1 O atoms)

(1 O atoms) 16.00 amu / 1 O atom = 16.00 amu

2.02 amu + 16.00 amu =18.02 amu

The formula mass of Ammonia, $NH_3$ is [14.0 g/mol + 3.0 g/mol] = 17.0 g/mol.

The formula mass of $BeH_2$ = 11.028062 g/mol

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determine the total pressure of gas mixture the contains oxygen, nitrogen, and helium if the partial pressures of the gases are

timurjin [86]

0.922 atm is the total pressure of gas mixture that contains oxygen, nitrogen and helium gases.

Explanation:

Data given:

partial pressure of the oxygen p $O_{2}$ = 0.197 atm

partial pressure of the nitrogen gas p $N_{2}$ = 0.461 atm

partial pressure of the helium gas pHe = 0.264

total pressure P in the gas mixture= ?

We know that individual gases exert pressure on the mixture of gases independently. From Dalton's law of pressure it is said that sum of partial pressure of all the gases in the mixture equals its total pressure. So,

Ptotal = p $O_{2}$ + p $N_{2}$ + pHe

putting the values in the mixture:

Ptotal = 0.197 + 0.461+ 0.264

Ptotal = 0.922 atm

Total pressure is 0.922 atm.

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3 years ago

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The answer is ionic bond

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What hypothesis led to the discovery of the proton?

Lana71 [14]

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Which contains the greatest mass of oxygen: 0.75 mol of ethanol (C2H5OH), 0.60 mol of formic acid (HCO2H), or 1.0 mol of water (

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4 years ago

A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a

svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol$

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g$

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0

3 years ago