An independent variable is the variable you are changing in order to measure the dependent variable, which is what you are measuring.
In this example, the
independent variable: chemicals in solution
dependent variable: temperature of solution
Answer: Volume of benzene is: 22.8 cm cubed
Answer:
17.6510 L
Explanation:
First we should get the number of moles of helium here by Boyle's law
PV=nRT
P=750/760= 0.9868 atm
T=25+273=298 kelvin
R= 0.08206
V= 20L
so
n=PV/RT
n=0.9868×20/0.08206×298
n=0.80707 mol
Then use the same law
V=0.80707×0.08206×263/0.9869=
17.6510L
SO THE VOLUME WILL BE 17.6510 L
Answer:
9.4
Explanation:
The equation for the reaction can be represented as:
+
⇄ 
The ICE table can be represented as:
+
⇄ 
Initial 0.27 0.49 0.0
Change -x -2x x
Equilibrium 0.27 - x 0.49 -2x x
We can now say that the concentration of
at equilibrium is x;
Let's not forget that at equilibrium
= 0.11 M
So:
x = [
] = 0.11 M
[
] = 0.27 - x
[
] = 0.27 - 0.11
[
] = 0.16 M
[
] = (0.49 - 2x)
[
] = (0.49 - 2(0.11))
[
] = 0.49 - 0.22
[
] = 0.27 M
![K_C = \frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_C%20%3D%20%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)


= 9.4
∴ The equilibrium constant at that temperature = 9.4