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Snezhnost [94]
4 years ago
6

A projectile leaves a gun at the same instant that the target is dropped from rest. If the projectile is initially aimed straigh

t at the target, will it hit the target?
Physics
1 answer:
enot [183]4 years ago
3 0

Depends on the mass of the projectile versus the object.

The force of gravity is dependent upon the mass of the object.  Therefore if the mass of the projectile and the mass of the object are exactly the same than both objects will fall at the same rate and will collide.  If the mass of the object is significantly larger than it will fall faster and the projectile will pass above it.  The opposite is true if the mass of the object is less than the mass of the projectile, in which case the projectile will pass underneath.

Lastly, this analysis excludes the force of wind resistance on the projectile and the object.  Under a complex model how the projectile travels through the air will have a separate impact that will alter its decent or rise outside of gravity.  For example, if the projectile is spinning it could "cut" into the wind and cause accelerated drop.  Think of a curve ball in baseball or a rising fastball.  

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Bart stole a watermelon in ran 5,000 feet from the cops to chase lasted 0.1 hours how fast was Bart running in miles per hour...
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4 years ago
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3 years ago
A bucket weighing 5 lbs is lifted at a constant rate from the bottom of a 100 ft well by a rope which weighs 5 lbs. The bucket h
8_murik_8 [283]

Answer:

W_{bucket} = 24934.85\,lbf\cdot ft

Explanation:

The system is modelled after the Principle of Energy Conservation and the Work-Energy Theorem:

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W_{bucket} = (5\,lb) (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft-0\,ft) + (25\,lb)\cdot (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft) - (30\,lb)\cdot (32.174\,\frac{ft}{s^{2}})\cdot (0\,ft)+(5\,lb) (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft-50\,ft)

W_{bucket} = 24934.85\,lbf\cdot ft

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Read 2 more answers
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