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pantera1 [17]
3 years ago
11

A can of sardines is made to move along an x axis from x = 0.47 m to x = 1.20 m by a force with a magnitude given by F = exp(–8x

), with x in meters and F in newtons. (Here exp is the exponential function.) How much work is done on the can by the force?
Physics
1 answer:
sattari [20]3 years ago
6 0
If the force were constant or increasing, we could guess that the speed of the sardines is increasing. Since the force is decreasing but staying in contact with the can, we know that the can is slowing down, so there must be friction involved.
Work is the integral of (force x distance) over the distance, which is just the area under the distance/force graph.
The integral of exp(-8x) dx that we need is (-1/8)exp(-8x) evaluated from 0.47 to 1.20 .

I get 0.00291 of a Joule ... seems like a very suspicious solution, but for an exponential integral at a cost of 5 measly points, what can you expect. On the other hand, it's not really too unreasonable. The force is only 0.023 Newton at the beginning, and 0.000067 newton at the end, and the distance is only about 0.7 meter, so there certainly isn't a lot of work going on. The main question we're left with after all of this is: Why sardines ? ?
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mash [69]

Answer:

2.63 cm

Explanation:

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c=\frac {F}{y}

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c=\frac {5.4 kg}{4.3 cm}=1.2558139534883720930232558139534883720930

By substitution now considering F to be 3.3 kg

y=\frac {3.3 kg}{1.2558139534883720930232558139534883720930}=2.6277777777777 cm\approx 2.63 cm

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4 years ago
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mart [117]

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Explanation:

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4 years ago
Consider a air-filled parallel-plate capacitor with plates of length 8 cm, width 5.52 cm, spaced a distance 1.99 cm apart. Now i
prohojiy [21]

Answer:

The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Explanation:

Given that,

Length of plates = 8 cm

Width = 5.52 cm

Distance = 1.99 cm

Dielectric constant = 2.6

Length = 4.4 cm

Potential = 0.8 V

We need to calculate the initial capacitance

Using formula of capacitance

C=\dfrac{\epsilon_{0}A}{d}

Put the value into the formula

C=\dfrac{8.85\times10^{-12}\times8\times5.52\times10^{-4}}{1.99\times10^{-2}}

C=1.96\times10^{-12}

We need to calculate the final capacitance

Using formula of capacitance

C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}

Put the value into the formula

C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}

C'=3.37\times10^{-12}

We need to calculate the  ratio of the new potential energy to the potential energy before the insertion of the dielectric

Using formula of energy

\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}

Put the value into the formula

\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}

\dfrac{E}{E'}=0.58

Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

4 0
3 years ago
A sample of gas has an initial volume of 23.6 l at a pressure of 1.52 atm . if the sample is compressed to a volume of 10.5 l: ,
nataly862011 [7]

New pressure=3.42 atm

Explanation:

using Boyle's law

P1 V1= P2 V2

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V1= initial volume

P2= final pressure

V2=final volume

23.6 (1.52)=P2 (10.5)

P2=3.42 atm

so final pressure= 3.42 atm

7 0
3 years ago
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ozzi

Answer:

4 cm/s

Explanation:

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Speed = Distance/Time

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3 years ago
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