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Fittoniya [83]
4 years ago
6

Why is it important to make observations about the reactants? ​

Chemistry
1 answer:
Free_Kalibri [48]4 years ago
7 0

Answer:

Reason Down below

Explanation:

It is important because when you make observation you get a clue sometimes and it  reactants i feel like it also takes places with observation. :)

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An example of an atom that has no charge is one that has
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<span>For an atom to have no charge, that is neutral, the number of electrons should be the same to the number of electrons. If the number of electron is more than the number of proton, the atom is negatively charged. Also, when the number of proton is more than the number of electron, the atom is positively charged. The answer to this item is letter C. </span>
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3 years ago
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Consider four small molecules, A–D, which have the following binding affinities for a specific enzyme (these numbers are the equ
ehidna [41]

Answer:

Binding affinity measures the strength of the interaction between a molecule to its ligand; it is expressed in terms of the equilibrium dissociation constant; and the higher value of this constant, the more weaker the binding between the molecule and the ligand is. On the other hand, small constans means that the interaction is tight. So "C" binds most tightly to the enzyme and "D" binds least tightly.

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4 years ago
From the data table given, calculate the missing quantity
ololo11 [35]

<u>Answer:</u> The initial volume of the gas is 16.55 mL

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=?mL\\T_1=300K\\V_2=16mL\\T_2=290K

Putting values in above equation, we get:

\frac{V_1}{300K}=\frac{16mL}{290K}\\\\V_1=\frac{16\times 300}{290}=16.55mL

Hence, the initial volume of the gas is 16.55 mL

4 0
4 years ago
What is the molarity of a NaOH solution if 28.2 mL of a 0.355 M H2SO4 solution is required to neutralize a 25.0-mL sample of the
Anni [7]

Answer:

A) 0.801

Explanation:

The reaction that takes place is:

  • 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

First we c<u>alculate the H₂SO₄ moles that reacted</u>:

  • 0.355 M * 28.2 mL = 10.011 mmol H₂SO₄

Now we <u>convert H₂SO₄ moles to NaOH moles</u>:

  • 10.011 mmol H₂SO₄ * \frac{2mmolNaOH}{1mmolH_2SO_4} = 20.022 mmol NaOH

Finally we <u>calculate the molarity of the NaOH solution</u>:

  • 20.022 mmol NaOH / 25.0 mL = 0.801 M

So the answer is option A.

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3 years ago
TRUE or FASLE: A strong electrolyte separates
natita [175]

Answer:

Explanation:

TRUE???

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