All categories

3 years ago

What are chemical formulas? Give an example of a chemical formula.

Chemistry

1 answer:

aniked [119]3 years ago

4 0

Explanation:

NaCl, HCl, NaOH, KCl, CH3COOH

You might be interested in

Calculate the number of moles when 3.00l of a gas at 814 mmhg and 25 °c?

Mariulka [41]

Volume=V=3L
Pressure=P=814mmHg
Temp=T=25°C

No of moles=n

$\\ \rm\rightarrowtail PV=nRT$

$\\ \rm\rightarrowtail n=\dfrac{PV}{RT}$

$\\ \rm\rightarrowtail n=\dfrac{814(3)}{25R}$

$\\ \rm\rightarrowtail n=2442/25R$

$\\ \rm\rightarrowtail n=97.7Rmol$

5 0

2 years ago

=:)

german

Answer:The Law of Conservation of Mass simply states that the total amount of mass should not change in a chemical reaction that is isolated (no other objects can enter the reaction). The total mass of the reactants must be equal to the total mass of the products. Thus, the correct estimate of the amount of oxygen used in the interaction is the difference between 133 g and 29 g.

Explanation: I hope this helped!

8 0

3 years ago

A fungus is an organism whose cells have a. nuclei. c. chlorophyll. b. cell walls. d. both (a) and (b).

andrew11 [14]

Answer:

cell walls

Explanation:

looked it up on google

6 0

3 years ago

A young deer needs cell division to grow to its full size. However, a deer's cells continue to divide through its whole life. Wh

Mumz [18]

Answer:

D :)

Explanation:

Cells die and the new cells that are being produced are replaced by new living cells. (If cell division prevented cancer, we'd all be saved by now.)

6 0

3 years ago

How much energy would be absorbed as heat by 25 g of iron when heated from 295 K to 306 K?

defon

Answer:

1.2 × 10² J

Explanation:

Given data

Mass of iron (m): 25 g

Initial temperature: 295 K

Final temperature: 306 K

The amount of heat (Q) that a substance absorbs depends on its specific heat capacity (c), which is the amount of heat energy required to raise the temperature of a substance per unit of mass. It can be calculated through the following expression. <em>(cFe = 0.444 J/g.K)</em>

$Q = c \times m \times (T_f-T_i) \\Q = \frac{0.444J}{g.K} \times 25g \times (306K-295K)\\Q = 1.2 \times 10^{2} J$

3 0

3 years ago