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sukhopar [10]
3 years ago
9

The lowest pitched sounds humans can generally hear have a frequency of roughly 20hz. what is the approximate wavelength of thes

e sound waves if their wave speed is 340m/s my
Physics
1 answer:
pantera1 [17]3 years ago
8 0

Wave speed  =  (wavelength) x (frequency)

     (340 m/s)  =  (wavelength) x (20/sec)

     (340 m/s) / (20/sec)  =  Wavelength

           17 meters            =  Wavelength

         (almost 56 feet !)
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During the first 50 s a truck traveled at constant speed of 25 m/s. Find the distance that it is traveled.
Allushta [10]
Time=50s
speed=25m/s

Distance = speed×time
=25×50
=1250m

DISTANCE TRAVELLED IS =1250m

6 0
2 years ago
A 40kg load is raised to a height of 25m. If the operation requires 1 min, find the power required​
OlgaM077 [116]

Answer:

163.33 Watts

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 40 Kg

Height (h) = 25 m

Time (t) = 1 min

Power (P) =..?

Next, we shall determine the energy. This can be obtained as follow:

Mass (m) = 40 Kg

Height (h) = 25 m

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E) =?

E = mgh

E = 40 × 9.8 × 255

E = 9800 J

Finally, we shall determine the power. This can be obtained as illustrated below:

Time (t) = 1 min = 60 s

Energy (E) = 9800 J

Power (P) =?

P = E/t

P = 9800 / 60

P = 163.33 Watts

Thus, the power required is 163.33 Watts

8 0
2 years ago
Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down th
Margaret [11]

Answer:

300 m

Explanation:

The train accelerate from the rest so u = 0 m/sec

Final speed that is v = 80 m/sec

Time t = 30 sec

The distance traveled by first plane = 1200 m

We know the equation of motion S=ut+\frac{1}{2}at^2 where s is distance a is acceleration and u is initial velocity

Using this equation for first plane 1200=0\times 30+\frac{1}{2}a30^2

a=2.67\frac{m}{sec^2}

As the acceleration is same for both the plane so a for second plane will be 2.67 \frac{m}{sec^2}

The another equation of motion is v^2=u^2+2as using this equation for second plane 40^2=0+2\times 2.67\times s

s = 300 m

5 0
2 years ago
Which of the following statements best describes energy conservation in heat engines?
Lorico [155]
B is the correct answer
5 0
2 years ago
An object 16.8 cm tall is placed in front of a converging lens. A real image, 46 cm tall, is formed on the other side of the len
worty [1.4K]

Answer:

2.74

Explanation:

Magnification = image distance/object distance

Mag = v/u

Given

v = 46cm

u = 16.8

Magnification = 46/16.8

Magnification = 2.74

Hence the magnification is 2.74

7 0
3 years ago
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