Answer: The weight of the air displaced by the balloon is less than the volume of the balloon.
Explanation:
A hot air balloon is a cloth wrap that contains several thousand cubic meters of air inside (a large volume of air). The burner heats the liquid propane to a gaseous state to generate a huge flame, which can reach more than 3 meters, thus heating the air mass inside the balloon. In this way,<u> its density is modified with respect to the air that surrounds it</u>, because the hot air is lighter than the outside air (less dense), causing the balloon to rise and float.
Now, if we know that the density of a body 
is directly proportional to its mass 
and inversely proportional to its volume 
:
We can deduce that <u>by increasing the volume of the body, its density will decrease.</u>
This is proof of <em><u>Archimedes' Principle</u></em>:
<em>A body totally or partially immersed in a fluid at rest, experiences a vertical upward thrust equal to the mass weight of the body volume that is displaced.</em>
In this case the fluid is the air outside. So, the warm air inside the balloon, being less dense, will weigh less than the outside air and therefore will receive an upward pushing force or thrust that will make the balloon ascend.
Answer:
D. On average, a woman's athletic ability peaks at a later age than a man's.
Explanation:
Answer:
the Answer is B
because the purpose of experimental conclusion it is to prove rather is a right or wrong is a hypothesis is right or wrong
Answer:
2.47 m/s backwards
Explanation:
From the law of conservation of momentum,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂...................... Equation 1
Where m₁ and m₂ = mass of the first basketball player and second basket ball player respectively, u₁ and u₂ = initial velocity of the first basket player and the second basketball player respectively, v₁ and v₂ = The final velocity of the first basket ball player and second basket ball player respectively.
Making v₁ the subject of the equation,
v₁ = (m₁u₁ + m₂u₂ - m₂v₂)/m₁.......................... Equation 2.
Given: m₁ = 87.2 kg, m₂ = 102.0 kg, u₁ = 7.0 m/s, u₂ = -5.2 m/s, v₂ = 2.9 m/s
Note: u₂ is negative because it moves towards the first basket ball player.
Substitute into equation 2
v₁ = [87.2(7.0)+102(-5.2) - (102×2.9)]/87.2
v₁ = (610.4-530-295.8)/87.2
v₁ = -215.4/87.2
v₁ = -2.47 m/s.
Thus the velocity of the 87.2 kg player = 2.47 m/s backwards.
Answer:
10 kg
Explanation:
The mass of an object does not change even if the amount of gravtiy changes.
