Answer:
Same magnitude of the 10 nc charge cause the electric field is external.
Explanation:
To do a better explanation, let's go and suppose we have an electric field of, 1300 N/C with a 10 nC charge.
As the system we are talking about is really big, and the charge is small, we can assume always if the charge is sitting right in the same point where the electric field is, then, the electric field would not suffer any kind of alteration in it's value. Therefore, no matter what value of the charge is sitting here, the electric field is independent of the charge, so it would not feel any alteration. However, the force that the charge is feeling would be stronger than in the first case.
F = qE
If charge is doubled, then the force would be bigger in the second case than in the first case, but electric field remain the same value.
En caso de una colisión de bajo nivel de gravedad podría golpearse con el tablero del carro o en la parte del sillón (si esta sentado en la parte trasera). Pero si es muy grave la colisión podría salirse del carro por el cristal.
(a) 
The change in energy of the transferred charge is given by:
where
q is the charge transferred
is the potential difference between the ground and the clouds
Here we have
So the change in energy is
(b) 7921 m/s
If the energy released is used to accelerate the car from rest, than its final kinetic energy would be
where
m = 950 kg is the mass of the car
v is the final speed of the car
Here the energy given to the car is
Therefore by re-arranging the equation, we find the final speed of the car:
Hi, thank you for posting your question here at Brainly.
This problem could be solved using this equation:
Diffraction limit = 1.22*wavelength/diameter
diameter = 0.8 cm = 0.008 m
wavelength = 500E-9 m
Diffraction limit = 1.22(500E-9)/0.008
Diffraction limit = 0.00007625
