The molarity of the solution of H₃PO₄ needed to neutralize the KOH solution is 0.35 M
<h3>Balanced equation </h3>
H₃PO₄ + 3KOH —> K₃PO₄ + 3H₂O
From the balanced equation above,
- The mole ratio of the acid, H₃PO₄ (nA) = 1
- The mole ratio of the base, KOH (nB) = 3
<h3>How to determine the molarity of H₃PO₄ </h3>
- Volume of acid, H₃PO₄ (Va) = 10.2 mL
- Molarity of base, Ca(OH)₂ (Mb) = 0.2 M
- Volume of base, Ca(OH)₂ (Vb) = 53.5 mL
- Molarity of acid, H₃PO₄ (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 10.2) / (0.2 × 53.5) = 1 / 3
(Ma × 10.2) / 10.7 = 1 / 3
Cross multiply
Ma × 10.2 × 3 = 10.7
Ma × 30.6 = 10.7
Divide both side by 30.6
Ma = 10.7 / 30.6
Ma = 0.35 M
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H20 can be a molecule or a compound because it is made up of Hydrogen(H)
and oxygen (O)
Answer:
1 tablet
Explanation:
Assuming that gm stands for gram:
Put everything in one unit, 0.3 g = 300 mg.
And given that each tablet is 300 mg:
mass/amount = 300mg / 1 tablet
300mg / X amount = 300mg / 1 tablet
(300mg/300mg) tablet = X = 1 tablet
So it is 1 tablet you need.
Answer:
I think it's B
Explanation:
I dont have much experience with the periodic table, but I just think its B.
