Answer:
You may, but it is too risky.
Even though you are being cautious around using electric equipment around water, you'll never know what can happen. You might accidentally drop that piece of electrical equipment you are using into the water. Water can be splashed around by someone or something without you noticing it and it may affect the object you are using. Sometimes, if water comes in contact with an electrical object, it may cause you electric shocks or the equipment you are using has a chance of exploding and may hurt you. You can guarantee that waterproof electrical equipment is safe to use, but it is better not to risk it too much.
Answer:
Density of the liquid = 1470.43 kg/m³
Explanation:
Given:
Mass of solid sphere(m) = 6.1 kg
Density of the metal = 2600 kg/m³
Thus volume of the liquid :
Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³
The volume of water displaced is equal to the volume of sphere (Archimedes' principle)
Volume displaced = 0.002346 m³
Buoyant force =
Where
is the density of the fluid
g is the acceleration due to gravity
V is the volume displaced
The free body diagram of the sphere is shown in image.
According to image:
Acceleration due to gravity = 9.81 ms⁻²
Tension force = 26 N
Applying in the equation to find the density of the liquid as:
<u>Thus, the density of the liquid = 1470.43 kg/m³</u>
Answer:
24.9%
Explanation:
According to this question, mole fraction of NaCl in an aqueous solution is 0.0927. This means that the mole percent of NaCl in the solution is:
0.0927 × 100 = 9.27%
Let's assume that the solution contains water (solvent) + NaCl (solute), hence, the mole fraction of water will be;
100% - 9.27% = 90.73%
THEREFORE, it can be said that, NaCl contains 0.0927moles while H2O contains 9.073moles
N.B: mole = mass/molar mass
Given the Molar Mass
NaCl: 58.44 g/mol
H2O: 18.016 g/mol
For NaCl;
0.0927 = mass/58.44
mass = 0.0927 × 58.44
5.42g
For H2O;
9.073 = mass/18.016
mass = 9.073 × 18.016
= 16.35g
Total mass of solution = 16.35g + 5.42g = 21.77g
Mass percent of NaCl = mass of NaCl/total mass × 100
% mass of NaCl = 5.42g/21.77g × 100
= 0.249 × 100
= 24.9%
To determine the amount of a certain element in a compound, we use the ratio of the elements from the compound. We calculate is follows:
45.0 g CCl4 ( 1 mol CCl4 / 153.82 g CCl4 ) ( 1 mol C / 1 mol CCl4 ) ( 12.01 g C / 1 mol C ) = 3.5135 g carbon present
Hope this answers the question. Have a nice day.
the answer you have chosen is correct
