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valkas [14]
3 years ago
14

Which of the following is not a renewable resource 1. gold 2. salmon 3. mahogany 4. fresh water

Chemistry
1 answer:
Delicious77 [7]3 years ago
3 0
<span>A: GOLD is not a renewable resource.hope this helps

</span>
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Which statement about the surface of the moon is true?
Anna [14]

Answer:

There is no air, wind, liquid water or life on the moons surface.

Explanation:

8 0
3 years ago
What is keq for the reaction 2so2(g) + o2(g) 2so3(g)? apex?
Dennis_Churaev [7]
The  keg for the reaction
2  SO2(g) + O2(g)   →  2  SO3(g)  is

 Keg =  [SO3]^2/ {(SO2)^2 ( O2)}

Keg (equilibrium constant)  is the ratio of  of equilibrium  concentration  of the product   raised  to the power  of their  stoichiometric  coefficient  to the  equilibrium  concentration  of the reactant  raised  to the power  of  their stoichiometric  coefficient.

7 0
3 years ago
Read 2 more answers
The temperature is -14°C the air pressure in an automobile tire is 149K PA if the volume does not change what is the pressure af
Jet001 [13]

Answer: The pressure after the tire is heated to 17.3°C is 167 kPa

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=149kPa\\T_1=-14^0C=(273-14)=259K\\P_2=?=27.5psi\\T_2=17.3^0C=(273+17.3)=290.3K

Putting values in above equation, we get:

\frac{149}{259}=\frac{P_2}{290.3}\\\\P_2=167kPa

Hence, the pressure after the tire is heated to 17.3°C is 167 kPa

4 0
3 years ago
If a sample of N2 gas has an initial pressure of 500 Torr and volume of 0.5 L, what will the final volume be if the pressure is
kherson [118]

Answer:

V₂ = 0.4 L

Explanation:

<u>Data:</u>

  • P₁ (initial pressure) = 500 torr
  • V₁ (initial volume) = 0.5 L
  • P₂ (final pressure) = 700 torr

<u>Wanted:</u>

  • V₂ (final volume)

<u>Equation:</u>

  • P₁V₁ = P₂V₂  →  V₂ = P₁V₁ / P₂

<u>Solution:</u>

  • V₂ = \frac{(500 torr)(0.5 L)}{700 torr} = 0.3571 L or 0.4 L
8 0
2 years ago
Volume increases, pressure stays the same, temperature
Mila [183]
Temperature decreases (?)
4 0
3 years ago
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