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Illusion [34]
3 years ago
15

Classify the following changes as physical or chemical changes. a. Water boils. b. Salt dissolves in water c. Milk turns sour d.

A metal rusts.
Chemistry
1 answer:
geniusboy [140]3 years ago
6 0

Answer:

Water boils - physical change

Salt dissolves in water- chemical change

Milk turns sour- chemical change

metal rusts - chemical change

Explanation:

A chemical change refers to changes that are irreversible and the process involves the evolution of heat along with the formation of a new substance, examples include;Salt dissolves in water, Milk turns sour, metal rusts etc

The boiling of water is a physical change. The water can be cooled and the vapour condensed,hence, the boiling of water is a physical change.

Physical changes are easily reversible and no new substance is formed.

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uranmaximum [27]
Density= mass/volume
volume=mass/density
volume= 40.0g/1.114g per mL
volume= 35.90664273 mL
volume = 35.9 mL
6 0
3 years ago
Describe 3 ways abrasion occurs in nature
kumpel [21]
There are three ways of abrasion occurs in nature; the wind, waves, and gravity. Abrasion is the mechanical process of wearing away of a rock surface and the movement of the particles while transporting through the wind, waves, and gravity.
7 0
3 years ago
Which family is made up of all radioactive elements
VARVARA [1.3K]

Answer:

actinide family

Explanation:

3 0
3 years ago
under certain water​ conditions, the free chlorine​ (hypochlorous acid,​ hocl) in a swimming pool decomposes according to the la
ivolga24 [154]

Answer:

1.7 ppm

Explanation:

Original amount N' = 2.6 ppm

time to testing t = 24 hr

final amount N = 2.1 ppm

Using exponential inhibited decay, we have

N = N'e^(-kt)

Where

N is the new reading

N' is the original reading

t is the decay time

k is the decay constant

Substituting, we have

2.1 = 2.6 x e^(-k x 24)

2.1 = 2.6 x e^(-24k)

0.808 = e^(-24k)

We take the natural log of both sides of the equation

Ln 0.808 = Ln (e^(-24k))

-0.213 = - 24k

K = 0.213/24 = 0.00886

After 48 hrs, the reading of free chlorine will be

N = 2.6 x e^(-0.00886 x 48)

N = 2.6 x e^(-0.425)

N = 2.6 x 0.654

N = 1.7 ppm

5 0
3 years ago
Cuantos moles de CO2 se requieren para reaccionar con 2 moles de Ba (OH)2
EastWind [94]

Answer:

hola soy jess, tu respuesta esta aqui

¿cuantos moles de CO2 se requiere para reaccionar 2 moles de Ba(OH)2

2 mol Ba(OH)₂ × \frac{1molCO_{2} }{1molBa (OH)_{2}}

1molBa(OH)

2

1molCO

2

= 2 moles CO₂

Explanation:

espero que pueda ayudarte

hermana/hermano

lo que

hahahaha

3 0
3 years ago
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