Answer:
7.22 x 10²³molecules
Explanation:
Given parameters:
Number of moles of hydrogen = 1.2moles
Unknown:
Number of molecules of hydrogen = ?
Solution:
From the concept of moles, a mole of a substance contains the Avogadro's number of particles.
1 mole of a substance = 6.02 x 10²³ molecules;
So; 1.2 moles of hydrogen = 1.2 x 6.02 x 10²³ molecules;
= 7.22 x 10²³molecules
Answer:
1) 2,1,2
2) 2,2,1,1
3)2,1,2
4)2,2,3
5)2,3,1,3
6 [ I cannot answer that]
7)6,1,2
Answer:
19.3 g/mL
Explanation:
The following data were obtained from the question:
Mass (m) = 12.4 kg
Volume (V) = 642 mL.
Density (D) =.?
Next, we shall convert 12.4 kg to grams. This can be obtained as follow:
1 kg = 1000 g
Therefore,
12.4 kg = 12.4 × 1000
12.4 kg = 12400 g
Therefore, 12.4 kg is equivalent to 12400 g.
Finally, we shall determine the density of the gold as follow:
Density is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:
Density (D) = mass (m) / volume (V)
D = m/V
With the above formula, the density of gold can easily be obtained as follow:
Mass (m) = 12400 g
Volume (V) = 642 mL.
Density (D) =.?
D = m/V
D = 12400/642
D = 19.3 g/mL
Therefore, the density of hold is 19.3 g/mL
C=λν ==> λ=c/ν
λ= 3x10^8 m/s / 1.50 x 10^15 s^-1
λ= 2 x 10^-7 m
λ= 200 nm
Answer:
![[CO]=[Cl_2]=0.01436M](https://tex.z-dn.net/?f=%5BCO%5D%3D%5BCl_2%5D%3D0.01436M)
![[COCl_2]=0.00064M](https://tex.z-dn.net/?f=%5BCOCl_2%5D%3D0.00064M)
Explanation:
Hello there!
In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:
![K=\frac{[CO][Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BCO%5D%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
Which can be written in terms of x, according to the ICE table:
Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:
![[COCl_2]=0.015M-0.01436M=0.00064M](https://tex.z-dn.net/?f=%5BCOCl_2%5D%3D0.015M-0.01436M%3D0.00064M)
Regards!
