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OleMash [197]
3 years ago
10

A ball is thrown straight up from a point 2 m above the ground. The ball reaches a maximum height of 3 m above its starting poin

t and then falls 5 m to the ground. When the ball strikes the ground, what is its displacement from its starting point?
Physics
1 answer:
qwelly [4]3 years ago
8 0

Answer:

2 m

Explanation:

The displacement of any body is the shortest distance in an object's path between its initial and final point.

The ball would travel 3 m from the point of throwing then fall down 5 m to the ground. The total distance traveled is 7 m.

The displacement of the ball will be the distance from the point of throwing to the ground i.e., 2 m as it is the shortest distance between the initial and final point of the ball's journey.

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A worker on the roof of a house drops his 0.46 kg hammer, which slides down the roof at constant speed of 9.88 m/s. The roof mak
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Answer:

The horizontal distance travelled in that time lapse is 12.94 m

Explanation:

In order to solve this problem, we'll need:

  1. The horizontal speed
  2. the time the hammer takes to fall from the roof to the ground

At the lowest point of the roof, the hammer has a 9.88 m/s speed that makes an angle of 27° with the horizontal, so we can calculate the horizontal and vertical speed with trigonometry. If we take right as x positive and down as y positive we get

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x(t)=8.8 m/s *t

y(t)=4.49m/s*t+\frac{1}{2}*9.8m/s^{2}*t^{2}

Now we calculate the time the hammer takes to get to the floor

17.1m=4.49m/s*t+\frac{1}{2}*9.8m/s^{2}*t^{2}\\t=1.47s or t=-2.38s

Now, we keep the positive time result and calculate the horizontal distance travelled

x(1.47s)=8.8m/s*1.47s=12.94m

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