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3 years ago

a body of mass 3kg is dropped from a height 15m.what would be the velocity of the body at 10m of height? take g=10m/s

Physics

1 answer:

mixer [17]3 years ago

5 0

Answer:

Explanation:

using v^2 = u^2 +2AS here : v = ? , u = 0 , a = 10 , s = 10. v*v = 0 + 2 (100) v^2 = 200 v = $\sqrt{200$ therefore , v = 14.14 m/s

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dimaraw [331]

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3 years ago

A 14.3-g bullet is fired into a 5.21 kg block of wood. The block is attached to a spring that has a spring force constant of 450

Natasha2012 [34]

Answer:

The initial speed of the bullet is $v_{o} = 889.199\,\frac{m}{s}$ .

Explanation:

The collision between bullet and block is inelastic and let suppose that motion occurs on a horizontal surface, so that changes in gravitational potential energy can be neglected. Initially, the intial speed of the bullet-block system can be determined with the help of the Work-Energy Theorem and the Principle of Energy Conservation:

$K = U_{k} + W_{loss}$

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The initial speed of the bullet-block system is:

$v \approx 2.383\,\frac{m}{s}$

Now, the initial speed of the bullet is determined by applying the Principle of Momentum Conservation:

$(0.014\,kg)\cdot v_{o} = (5.224\,kg)\cdot \left(2.383\,\frac{m}{s} \right)$

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3 years ago

a body of mass 3kg is dropped from a height 15m.what would be the velocity of the body at 10m of height? take g=10m/s​

a body of mass 3kg is dropped from a height 15m.what would be the velocity of the body at 10m of height? take g=10m/s