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4 years ago

Solve for x in the equation 2x^2-5+1=3

Mathematics

1 answer:

icang [17]4 years ago

3 0

Answer:

x = 2

Step-by-step explanation:

Given

2x^2-5+1=3

Combine like terms

-5 + 1 = -4

2x^2 - 4 = 4

Add 4 to both sides

2x^2 = 8

Divide both sides by 2

8/2 = 4

Simplify

x^2 = 4

Square both sides

$\sqrt{x^2} = x$

$\sqrt{4}=2$

Simplify

x = 2

Answer

x = 2

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3 years ago

Use the counting principle to determine the number of elements in the sample space. The possible ways to complete a multiple-cho

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Step-by-step explanation:

Step 1

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4 years ago

Solve the equation: k^2+5k+13=0

mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\$

From the question

a = 1 , b = 5 , c = 13

So we have

$k = \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)} \\ = \frac{ - 5 \pm \sqrt{25 - 52} }{2} \\ = \frac{ - 5 \pm \sqrt{ - 27} }{2} \: \: \: \: \: \: \\ = \frac{ - 5 \pm3 \sqrt{3} \: i}{2} \: \: \: \: \: \:$