Answer:
E(x) = 1.43 (Approx)
Step-by-step explanation:
Given:
Total number of camera = 7
Defective camera = 5
Sample selected = 2
Computation:
when x = 0
P(x=0) = 2/7 × 1/6 = 2/42
P(x=1) = [2/7 × 5/6] + [5/7 × 2/6] = 20/42
P(x=2) = 5/7 × 4/6 = 20/42
So,
E(x) = [0×2/42] + [1×20/42] + [2×20/42]
E(x) = 1.43 (Approx)
I think I could be letter C
Let l, t, b represent the numbers of lions, tigers, bears, respectively.
2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals
_____
The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
.. -l = -48
There are 48 lions, 3 tigers, and 17 bears.
Slope=(y1-y2)/(x1-x2)
(1 - 5)/(3 - -2)=(1 - 5)/(3 + 2)
-4/5
A is the answer
