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finlep [7]
3 years ago
12

15 POINTS PLEASE HELP

Mathematics
2 answers:
dezoksy [38]3 years ago
3 0

Answer:

20

Step-by-step explanation:

4*2+6*2=20

defon3 years ago
3 0
The answer to the problem above would be D. 20km
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Which of the following numbers would appear between 0.1 and 1.0 on the number line?
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There are an infinite set of values which would work
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If the area of a circle is 16π meters, what is the diameter? *
Lera25 [3.4K]

Answer:

When the diameter is given you just take half of it so simply put what is half of 16pi and it will give your answer. :)

Step-by-step explanation:

7 0
3 years ago
Solve the equation!3 tan^3θ = tan θ
andreev551 [17]
3 tan³ t(theta) = tan t(theta)
3 tan³ t - tan t = 0
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tan t = 0
t 1 = k π ,  k ∈ Z
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8 0
3 years ago
26. If the area of the rectangle shown below is given by the expression 3x + 7x - 6,
Crazy boy [7]

Answer:

D=(3x-2)

Step-by-step explanation:

Area=length×width =3x²+7x-6

thus a=3 b=7 c=-6

W=(x+3)

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check if its correct.

3x-2×x+3

x(3x-2)+3(3x-2)

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6 0
3 years ago
In a certain computer, the probability of a memory failure is 0.01, while the probability of a hard disk failure is 0.02. If the
ratelena [41]

Answer:

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

Step-by-step explanation:

For this case we can define the following events:

A= In a certain computer a memory failure

B= In a certain computer a hard disk failure

We have the probability for the two events given on this case:

P(A) = 0.01 , P(B) = 0.02

We also know the probability that the memory and the hard drive fail simultaneously given by:

P(A \cap B) = 0.0014

And we want to check if the two events are independent.

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

8 0
3 years ago
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