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Vinil7 [7]
3 years ago
5

Look at the image below:

Chemistry
1 answer:
PIT_PIT [208]3 years ago
7 0

Answer:

The figure is a molecule and a compound

Explanation:

Because it have 2 cluster molecules

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Solutions of hydrochloric acid caused the light bulb to glow brighter than solutions of acetic acid. how do you account for the
maksim [4K]
<span>The primary difference between hydrochloric acid and acetic acid is that hydrochloric acid undergoes a complete ionization, whereas acetic acid does not. This is why a light bulb will burn brighter in the solutions of hydrochloric acid, and also why hydrochloric acid is considered a strong acid, while acetic acid is considered a weak acid.</span>
7 0
3 years ago
HELPPPP MEEE PLEASEEE!!!!!!
MrRa [10]
Mass =70 ( Mass of protons=1 ,Mass of neutrons =1, Mass of electron =0.0005(can be ignored))
Therefore, 40 +30=70
Charge= -2 ( it is taking in/attracting electrons to its shell) base on the proton number you are able to identify if it is attracting or releasing an electron, if the electron number is more than proton number then it is attracting therefore resulting in a negative charge vice versa for releasing an electron.
5 0
4 years ago
A salad including lettuce, tomatoes, and onions would be classified as a
Whitepunk [10]

Answer:

C)Mixtured

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4 0
3 years ago
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔGo:reactio
koban [17]

Answer:

Explanation:

glucose-1-phosphate  →  glucose-6-phosphate,  ΔGo = -7.28 kJ/mol

fructose-6-phosphate → glucose-6-phosphate,    ΔGo = -1.67 kJ/mol

subtracting the equation

glucose-1-phosphate - fructose-6-phosphate  = 0 , ΔGo =  -7.28  - ( -1.67 ) kJ / mol

glucose-1-phosphate  = fructose-6-phosphate      ΔGo  = - 5.61 kJ / mol

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K = 9.63 .

3 0
3 years ago
a photon has an energy of 1.10 x 10_-13 J. What is the photon's wavelenght? What type of electromagnetic radiation is it?
Luden [163]

Answer:

λ  = 0.002 nm

The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.

Explanation:

Given data:

Energy of photon = 1.10 × 10⁻¹³ J.

Wavelength of photon = ?

Solution:

Formula:

E = h.c / λ

λ  = h. c / E

λ  = 6.626 × 10⁻³⁴ j. s × 3×10⁸ m/s / 1.10 × 10⁻¹³ J.

λ  = 19.878 × 10⁻²⁶m /  1.10 × 10⁻¹³ J

λ  = 18.071 × 10⁻¹³ m

λ  = 18.071 × 10⁻¹³  × 10⁹

λ  = 18.071 × 10⁻⁴ nm

λ  = 0.002 nm

The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.

8 0
4 years ago
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