Answer:- The gas needs to be transferred to a container with a volume of 11.2 L.
Solution:- From Boyle's law. "At constant temperature, Volume is inversely proportional to the pressure."
It means, the volume is decreased if the pressure is increased and vice versa.
Here, the Pressure is decreasing from 537 torr to 255 torr. So, the volume must increase and calculated by using the equation:
Where, 
is initial pressure and 
is final pressure. Similarly, 
is initial volume and 
is final volume.
Let's plug in the values in the equation:
(537 torr)(5.30 L) = (255 torr)()
= 11.2 L
So, the new volume of the container needs to be 11.2 L.
Answer:
Explanation:
Molar mass of NaCl = (23+35.5)
Molar mass of NaCl = 58.5g/mol
Molar mass of C12H22011
= 12(12) + 22(1) + 16(11)
= 144 +22 + 176
= 342g/mol
First, find the total mass.
34.5 g + 18.2 g + 2.6 g = 55.3 g
Divide the mass of each element by total mass.
34.5 g / 55.3 g = .62 x 100 = 62% element a
18.2 g / 55.3 = .33 x 100 = 33% element b
2.6 g / 55.3 = .047 x 100 = 4.7% element c
Hope I helped!
Answer:
2.25g of NaF are needed to prepare the buffer of pH = 3.2
Explanation:
The mixture of a weak acid (HF) with its conjugate base (NaF), produce a buffer. To find the pH of a buffer we must use H-H equation:
pH = pKa + log [A-] / [HA]
<em>Where pH is the pH of the buffer that you want = 3.2, pKa is the pKa of HF = 3.17, and [] could be taken as the moles of A-, the conjugate base (NaF) and the weak acid, HA, (HF). </em>
The moles of HF are:
500mL = 0.500L * (0.100mol/L) = 0.0500 moles HF
Replacing:
3.2 = 3.17 + log [A-] / [0.0500moles]
0.03 = log [A-] / [0.0500moles]
1.017152 = [A-] / [0.0500moles]
[A-] = 0.0500mol * 1.017152
[A-] = 0.0536 moles NaF
The mass could be obtained using the molar mass of NaF (41.99g/mol):
0.0536 moles NaF * (41.99g/mol) =
<h3>2.25g of NaF are needed to prepare the buffer of pH = 3.2</h3>
I think it’s light
Have fun :)
