<span>The primary difference between hydrochloric acid and acetic acid is that hydrochloric acid undergoes a complete ionization, whereas acetic acid does not. This is why a light bulb will burn brighter in the solutions of hydrochloric acid, and also why hydrochloric acid is considered a strong acid, while acetic acid is considered a weak acid.</span>
Mass =70 ( Mass of protons=1 ,Mass of neutrons =1, Mass of electron =0.0005(can be ignored))
Therefore, 40 +30=70
Charge= -2 ( it is taking in/attracting electrons to its shell) base on the proton number you are able to identify if it is attracting or releasing an electron, if the electron number is more than proton number then it is attracting therefore resulting in a negative charge vice versa for releasing an electron.
Answer:
Explanation:
glucose-1-phosphate → glucose-6-phosphate, ΔGo = -7.28 kJ/mol
fructose-6-phosphate → glucose-6-phosphate, ΔGo = -1.67 kJ/mol
subtracting the equation
glucose-1-phosphate - fructose-6-phosphate = 0 , ΔGo = -7.28 - ( -1.67 ) kJ / mol
glucose-1-phosphate = fructose-6-phosphate ΔGo = - 5.61 kJ / mol
- ΔGo = RT lnK
5.61 x 10³ = 8.31 x 298 x lnK
lnK = 2.265
K = 9.63 .
Answer:
λ = 0.002 nm
The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.
Explanation:
Given data:
Energy of photon = 1.10 × 10⁻¹³ J.
Wavelength of photon = ?
Solution:
Formula:
E = h.c / λ
λ = h. c / E
λ = 6.626 × 10⁻³⁴ j. s × 3×10⁸ m/s / 1.10 × 10⁻¹³ J.
λ = 19.878 × 10⁻²⁶m / 1.10 × 10⁻¹³ J
λ = 18.071 × 10⁻¹³ m
λ = 18.071 × 10⁻¹³ × 10⁹
λ = 18.071 × 10⁻⁴ nm
λ = 0.002 nm
The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.