KOH is an alkali metal hydroxide and so would be a strong base. HCl is a hydrogen halide in solution, which would be a strong acid (the exception would be HF). There are no other strong bases or acids in this list, so these two substances will comprise our bookends.
KNO3 is a salt produced during the neutralization reaction between KOH and HNO3; the former is (as we just noted) a strong base, and the latter is a strong acid. The salt consisting of the conjugate acid and base of a strong base and acid, respectively, produces a neutral solution in water. So, the KNO3 would be neutral.
KCN in solution consists of the ions K+ and CN-; K+, as we just went through, is the conjugate acid of KOH, a strong base. CN- is the conjugate base of HCN, a weak acid in solution. Since the resultant salt, KCN, is the neutralization product of a strong base and a weak acid, it will be slightly basic in solution (the CN- is a stronger base than K+ is as an acid). So, the KCN solution would be slightly basic.
NH4Cl dissociates in solution to give NH4+ and Cl-. NH4+, as the conjugate acid of the weak base ammonia, NH3, will donate an H+ in water. Cl- is the conjugate base of a strong acid, HCl. The neutralization product of a strong acid (HCl) and a weak base (NH3) would be slightly acidic. So, the solution of NH4Cl would be slightly acidic.
Ranking the solutions from most acidic to most basic (note: it’s important that the solutions have the same concentrations), we get:
HCl (strong acid)
NH4Cl (weak acid salt)
KNO3 (neutral salt)
KCN (weak basic salt)
KOH (strong base).
Explanation:
H2So4=sulphuric acid , strong acid
Answer:
So you should go and try to divide or smth or multiply
A) 0 charge. Remember Neutron- Neutral charge
Answer:
Take for example I₂ (iodine)
Explanation:
It has only a pair of electrons between the iodine atoms in order to gain a stable arrangement of 8 electrons in its outer shell. It is sharing them, so it's a covalent bond as a single iodine atom cannot be stable on its own. It's a halogen and is a single covalently-bonded diatomic molecule.
Similarly, take oxygen. IT needs two pairs of electrons just so it can reach a stable outer shell of 8 electrons. If it doesn't then it cannot be stabilised so it must be bonded with another oxygen atom and share two electrons.