Answer:
When the temperature is decreased by a factor of three, the volume will decrease as well by a factor of 3. In this situation, the new volume will be 26.33 L
Explanation:
Step 1: Data given
Volume of the container = 79.00 L
Temperature in the container = 352 K
The pressure and number of moles is constant.
The temperature is decreased by a factor of three
Step 2: Calculate the volume
V1/T1 = V2/T2
⇒with V1 = the initial volume = 79.00L
⇒with T1 = the initial temperature = 352 K
⇒with V2 = the final volume = TO BE DETERMINED
⇒with T2 = the final volume = T1/3 = 117.3 L
V2 = ((1/3 * T1) / V1) *T2
V2 = V1/3
79.00 / 352 = V2 / 117.3
V2 = 26.33
When the temperature is decreased by a factor of three, the volume will decrease as well by a factor of 3. In this situation, the new volume will be 26.33 L
