Answer:
0.435 N
The centripetal force increases by a factor of 4
Explanation:
Let the centripetal force be F
F =mv^2/r
m= mass of the object
v = linear velocity of the object
r = radius of the circular path
but v = 2πr/T = 2 * 3.142 * 0.147 / 0.388
v = 2.38 m/s
F = 0.0113 * (2.38)^2/0.147
F= 0.435 N
if v= 2v
Then;
F = m(2v)^2/r
F = m4v^2/r
F= 4mv^2/r
The centripetal force increases by a factor of 4
An object will remain at rest or keep moving with a constant velocity unless a force acts on it. Your Welcome ;)
<span>x = 129.9 m
y = 30.9 m
First, let's calculate the horizontal and vertical velocities involved
h = 50.0cos(30) = 43.30127 m/s
v = 50.0sin(30) = 25 m/s
The horizontal distance is simply the horizontal velocity multiplied by the time, so
43.30127 m/s * 3 s = 129.9 m
So the horizontal distance traveled is 129.9 m, so x = 129.9 m
The vertical distance needs to take into account gravity which provides an acceleration of -9.8 m/s^2, so we get
d = 25 m/s * 3s - 0.5*9.8 m/s^2 * (3 s)^2
d = 75 m - 4.9 m/s^2 * 9 s^2
d = 75 m - 44.1 m
d = 30.9 m
So the vertical distance traveled is 30.9 m, so y = 30.9 m</span>
Answer:
A,B,D,E,F
Explanation:
I took the test for yall.