Answer:
The beach ball's velocity at the moment it was tossed into the air is <u>4.9 m/s.</u>
Explanation:
Given:
Time taken by the ball to reach maximum height is, ![t=0.50\ s](https://tex.z-dn.net/?f=t%3D0.50%5C%20s)
We know that, velocity of an object at the highest point is always zero. So, final velocity of the ball is, ![v=0\ m/s](https://tex.z-dn.net/?f=v%3D0%5C%20m%2Fs)
Also, acceleration acting on the ball is always due to gravity. So, acceleration of the ball is, ![a=g=-9.8\ m/s^2](https://tex.z-dn.net/?f=a%3Dg%3D-9.8%5C%20m%2Fs%5E2)
The negative sign is used as acceleration is a vector and it acts in the downward direction.
Now, we have the equation of motion relating initial velocity, final velocity, acceleration and time given as:
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
Where, 'u' is the initial velocity.
Plug in the given values and solve for 'u'. This gives,
![0=u-9.8(0.5)\\u=9.8\times 0.5\\u=4.9\ m/s](https://tex.z-dn.net/?f=0%3Du-9.8%280.5%29%5C%5Cu%3D9.8%5Ctimes%200.5%5C%5Cu%3D4.9%5C%20m%2Fs)
Therefore, the beach ball's velocity at the moment it was tossed into the air is 4.9 m/s