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telo118 [61]
3 years ago
11

What are 3 parts of daltons atomic theory ?

Physics
1 answer:
Crank3 years ago
7 0
1) all matter is made of atoms , atoms are indivisible and indestructible 2) compounds are formed by a combination of two or more different kinds of atoms 3) a chemical reaction is an arrangement of atoms
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Which of the following correctly describes the relationship between current and voltage as the voltage of a battery increases. R
Y_Kistochka [10]

Answer:_COC1\/2+_H\/2O>_HC1+CO\/2

Explanation:

Need help asap

3 0
3 years ago
A child is prescribed a drug X; the recommended manufacturer’s dose is 2.50 mg/m2. The body surface area (BSA) of the child is 1
guapka [62]

Answer: 3.75 mg

Explanation:

We need a dose of 2.50 mg per square meter of BSA, and we also know that the BSA of the child is 1.50 m^2, then if the dosage should be 2.50mg for one m^2, for 1,5 m^2 we should administrate an amount of:

D = 1.5 m^2*(2.50mg/m^2) = 1.5*2.5 mg = 3.75 mg

3 0
3 years ago
What is the main function of a telescope?
Gwar [14]

Answer:

Explanation:The main purpose of astronomical telescope is to make objects from outer space appear as bright, contrasty and large as possible. That defines its three main function: light gathering, resolution and magnification. These are the measure of its efficiency.

3 0
3 years ago
A toy dart gun has a spring with k= 128 N/m. How much force does it take to pull the spring back 0.0500 m? (Unit = N)​
yKpoI14uk [10]

Answer:

F = 0.64 N

Explanation:

We are given;

Spring constant constant; k = 1.28 N/m

Distance; x = 0.5 m

From Hooke's law, we know that F = kx.

Thus;

F = 1.28 × 0.5

F = 0.64 N

Thus, force it takes to pull the spring back = 0.64 N

4 0
3 years ago
Read 2 more answers
What length of a certain metal wire of diameter 0.15 mm is needed for the wire to have a resistance of 15 ω? the resistivity of
Murljashka [212]

The resistance of the cylindrical wire is R=\frac{\rho l}{A}.

Here R is the resistance, l is the length of the wire and A is the area of cross section. Since the wire is cylindrical A=\frac{\pi d^2}{4} . Rearranging the above equation,

A=\frac{\rho l}{R}\\  \frac{\pi d^2}{4}=\frac{\rho l}{R}\\  l=\frac{\pi d^2 R}{4 \rho}

Here d=0.15, R=15, \rho=1.68(10^{-8}).

Substituting numerical values,

l=\frac{\pi 0.15^2(10^{-6}) (15)}{4 (1.68)(10^{-8})}  \\ l=15.78

The length of the wire is 15.78 \;\;m

5 0
4 years ago
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