Answer:
286
Explanation:
p1v1/T1=p2v2/T2
then subtitude your values
T2=760*0.65*273/210*0.040
T2=135/8.4=16+273=289
Answer:
a) ΔV = 20 V
, b) Q = 35.4 10⁻⁹ C, c) C = 1.77 10⁻⁹ F
Explanation:
a) The electric potential is
ΔV = E x
ΔV = 4.0 10⁵ 50 10⁻⁶
ΔV = 20 V
c) The capacity of a capacitor is
C = ε₀ A / d
The area of a square plate is
A = L²
A = 0.10²
A = 0.01 m²
L = 50mm = 50 10⁻⁶ m
Let's calculate
C = 8.85 10⁻¹² 0.01 /50 10⁻⁶
C = 1.77 10⁻⁹ F
b) the charge is
Q = C ΔV
Q = 1.77 10⁻⁹ 20
Q = 35.4 10⁻⁹ C
Answer:
a. 0.5307 sec
b. 0.4458 m
c. =
Explanation:
Horizontal Motion
It describes the dynamics of an object thrown horizontally in free air. The initial horizontal velocity is maintained all the time since no horizontal forces are acting. The initial vertical velocity is zero at launch time, but it grows downwards powered by the acceleration of gravity.
The object hits the ground at a distance x from the point of launching, after having traveled a vertical distance 
, taking a time t to complete the travel. The formulas who relate the different magnitudes are
The horizontal velocity 
is the same regardless of the elapsed time
The plate of apple pie left the counter at a speed
The counter is 
high.
a.
Knowing that
We use this formula to compute t
At the moment when the plate hits the floor y=0
Solving for t
b.
c.
53....................................
Explanation:
Take the object's starting direction of motion to be the positive direction, so that a stopping force acts in the opposite direction. By Newton's second law, the object undergoes an acceleration <em>a</em> such that
-15 N = (20 kg) <em>a</em>
Solve for <em>a</em> :
<em>a</em> = - (15 N) / (20 kg) = -0.75 m/s²
The object's velocity <em>v</em> at time <em>t</em> is then given by
<em>v</em> = 3 m/s + (-0.75 m/s²) <em>t</em>
so the time it takes for the object to slow to a rest is
0 = 3 m/s + (-0.75 m/s²) <em>t</em>
<em>t</em> = (3 m/s) / (0.75 m/s²) = 4.0 s
