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tatiyna
3 years ago
5

PLEASE HELP ME!!! I DON’T KNOW HOW TO DO THIS

Physics
1 answer:
Gennadij [26K]3 years ago
8 0
It looks like it's wanting you to find speed and velocity
these formula's should help
speed=distance/time
velocity=overall distance/time
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Hi,please i need help with this one in physics.hurry and correct i need it.<br>Topic:Equilibrium.​
Rudik [331]

The half-meter rule (easy math) is 0.5 meters or 50 centimeters since a meter is 1 meters long, which is equivalent to 100 centimeters. Therefore, we shall apply the 50 cm rule.

A 50 cm rule's center of mass is now 25 cm away.

Additionally, according to the data, the object is pivoted at 15 cm, while the 40 g object is hung at 2 cm from the rule's beginning. Using a straightforward formula, we can compare the two situations: the distance from the pivot to the center of the mass times the mass of the 40 g object divided by 2 cm must equal the distance from the pivot to the center of the mass times mass of the 10 x g object

The result of the straightforward computation must be 52g.

Most simplified version:

the center of mass of the rule is at the 25 cm mark

⇒ 40 g * (15 cm - 2 cm)

⇒ = M * (25 cm - 15 cm)

#SPJ2

5 0
2 years ago
The electric output of a power plant is 716 MW. Cooling water is the main way heat from the powerplant is rejected, and it flows
Stels [109]

Answer:

(a) 83475 MW

(b) 85.8 %

Explanation:

Output power = 716 MW = 716 x 10^6 W

Amount of water flows, V = 1.35 x 10^8 L = 1.35 x 10^8 x 10^-3 m^3

mass of water, m = Volume  x density = 1.35 x 10^8 x 10^-3 x 1000

                                                               = 1.35 x 10^8 kg

Time, t = 1 hr = 3600 second

T1 = 25.4° C, T2 = 30.7° C

Specific heat of water, c = 4200 J/kg°C

(a) Total energy, Q = m x c x ΔT

Q = 1.35 x 10^8 x 4200 x (30.7 - 25.4) = 3 x 10^12 J

Power = Energy / time

Power input = P = \frac{3 \times 10^{12}}{3600}=8.35 \times 10^{8}W

Power input = 83475 MW

(b) The efficiency of the plant is defined as the ratio of output power to the input power.

\eta =\frac{Power output}{Power input}

\eta =\frac{716}{83475}=0.858

Thus, the efficiency is 85.8 %.

7 0
3 years ago
How does the changing the distance between the objects affect the force between them
oksano4ka [1.4K]
The farther the distance, the weaker the gravitational force
4 0
4 years ago
Read 2 more answers
Henry ran a 100 m race. Use the graph to answer the following:
horrorfan [7]

Using the graph, which describes how Henry ran the 100m race;

a) It takes Henry 20seconds to run 100m

b) Henry's average speed over the race is; 5m/s.

According to the linear graph which describes the distance ran by Henry during the 100m race as a function of time.

a) Since the distance from start ran by Henry is plotted on the vertical axis, and the time is plotted on the horizontal axis;

To determine how long it took Henry to run 100m; The point corresponding to 100m is traced downward from the line of the graph and we find out that;

It takes Henry 20seconds to run 100m

b) Henry's average speed over the race is simply;

The slope of the distance-time graph.

Therefore,

  • Average speed = (100-0)/(20-0)

  • Average speed = 100/20

  • Average speed = 5m/s.

Therefore, Henry's average speed over the race is; 5m/s.

Read more:

brainly.com/question/22125199

6 0
2 years ago
Compare the maximum rate of heat transfer to the basal metabolic rate by converting a bmr of 88 kcal/hr into watts. what is the
elena-14-01-66 [18.8K]

Explanation :

It is given that,

BMR i.e basal metabolic rate is 88 kcal/hr. So, BMR in watts is converted by the following :

We know that, 1 kilocalorie = 4184 joules

So, 1\ kcal/h=\dfrac{1\times 4184\ J}{3600\ sec}

1\ kcal/h=1.16\ J/sec

J/sec is nothing but watts.

So, 1\ kcal/h=1.16\ watts

and 88\ kcal/h=88\times 1.16\ watts = 102.08\ watts

So, it can be seen that the body can accommodate a modes amount of activity in hot weather but strenuous activity would increase the metabolic rate above the body's ability to remove heat.

8 0
4 years ago
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