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3 years ago

8

Define neuron and nervecell

2 answers:

san4es73 [151]3 years ago

3 0

Answer: Hi!

A neuron is a basic working unit of the brain. Neurons are special cells designed to transfer information to other nerve, muscle, or gland cells. They are pretty cool - looking too! (A slightly irregular circular shape with branches reaching out from all sides.) A neuron is a nerve cell. Nerve cells are the way of communication in the nervous system.

Hope this helps!

Travka [436]3 years ago

3 0

Answer:

Explanation:

The basic unit of communication in the nervous system is the nerve cell (neuron). Each nerve cell consists of the cell body, which includes the nucleus, a major branching fiber (axon) and numerous smaller branching fibers (dendrites).

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Friction is just hot air rubbing off on the inevitable force of solid<br><br>prove me wrong

algol13

Answer:

lol ur not wrong

Explanation:

8 0

3 years ago

Read 2 more answers

The 88-lb force P is applied to the 210-lb crate, which is stationary before the force is applied. Determine the magnitude and d

Marina86 [1]

Answer:

$F=-88Ib$

Explanation:

From the question we are told that:

Force P=88Ib

Mass of crate M_c=210Ib

Generally the equation for Frictional force F is mathematically given by

$Friction\ force (f) = friction\ coefficient\ (u) * Normal\ reaction (N)$

$F=u*N$

with $\mu =0.47$

$F=98.7Ib$

Therefore since Static Friction supersedes applied force body remains at rest.

Frictional force =88Ib (negative)

$F=-88Ib$

5 0

3 years ago

A 2.2-kg block slides on a horizontal surface with a speed of v=0.80m/s and an

mina [271]

Answer:

μ = 0.33

Equal to 3.2 m/s²

Explanation:

Draw a free body diagram of the block. There are three forces:

Normal force N pushing up.

Weight force mg pulling down.

Friction force Nμ pushing opposite the direction of motion.

Sum of forces in the y direction.

∑F = ma

N − mg = 0

N = mg

Sum of forces in the x direction.

∑F = ma

Nμ = ma

Substitute.

mgμ = ma

μ = a/g

μ = (3.2 m/s²) / (9.8 m/s²)

μ = 0.33

As found earlier, the acceleration is a = gμ. Since g and μ are constant, a is also constant, so it does not change with velocity.

5 0

3 years ago

Mr Johnson launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how much time does it take

vazorg [7]

Answer:c

Explanation:

3 0

3 years ago

Calculate the force on the test charge by the +6μC charge. Hint: The force in the positive x-direction is positive and the neg

DIA [1.3K]

Answer:

The force on the test charge is 114.75 N.

Explanation:

Given that,

Test charge $q=6\ \mu C$

Suppose the test charge is 3.4 μC and the distance between the charge and test charge is 4.0 cm.

We need to calculate the force on the test charge

Using formula of electric force

$F=\dfrac{kqq_{1}}{r^2}$

Where, q = test charge

q₁ =charge

r = distance

Put the value into the formula

$F=\dfrac{9\times10^{9}\times6\times10^{-6}\times3.4\times10^{-6}}{(4.0\times10^{-2})^2}$

$F=114.75\ N$

Hence, The force on the test charge is 114.75 N.

6 0

4 years ago