Explain how to find the orginal and the new dimensions of an object when the scale changes
1 answer:
You might be interested in
Answer:
It is an example of a nonlinear function.
Step-by-step explanation:
Use a graphing calculator or graph the points and try to make a line, as it will not work
Answer:
The expression is ⇒ 2nd answer
Step-by-step explanation:
* Lets explain how to solve the problem
- In the exponent rules, we add the exponents when we multiply terms
have same base
- Ex:
- The volume of the rectangular box is the product of its three
dimensions
* Lets solve the problem
- John buys a water tank from a company
- The tank he buys has the dimensions b² by b^4 by 4c³
∵ The water tank is shaped a rectangular box
∵ The tank has dimensions
∵ The volume of the tank = L × W × H , where L , W , H are the
dimensions of the tank
- Assume that L = b² , W = and H = 4c³
∴ The volume of the tank = b² × × 4c³
- b² and b^4 has the same base, then add its exponents
∴ The volume of the tank = × 4c³
∴ The volume of the tank = × 4c³
∴ The volume of the tank =
* The expression which represents the volume of the tank is:
∴ The answer is the second expression
Answer:
<A = 41.4°
Step-by-step explanation:
Recall, SOH CAH TOA
Reference angle = <A
Hypotenuse length = 8
Adjacent length = 6
Since Hypotenuse and Adjacent are involved, we would apply CAH, which is:
Cos A = Adj/Hyp
Plug in the values
Cos A = 6/8
Cos A = 0.75
A = 41.4096221° ≈ 41.4° (nearest tenth)