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lukranit [14]
3 years ago
11

A student practicing for track ran 800 meter in 110 seconds. what was her speed?

Physics
1 answer:
adoni [48]3 years ago
3 0
Her speed was 7.27 meters per second
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A stone is catapulted at time t = 0, with an initial velocity of magnitude 19.9 m/s and at an angle of 39.9° above the horizonta
larisa [96]

Answer:

Part a)

x = 15.76 m

Part b)

y = 7.94 m

Part c)

x = 26.16 m

Part d)

y = 7.49 m

Part e)

x = 83.23 m

Part f)

y = -75.6 m

Explanation:

As we know that catapult is projected with speed 19.9 m/s

so here we have

v_x = 19.9 cos39.9

v_x = 15.3 m/s

similarly we have

v_y = 19.9 sin39.9

v_y = 12.76 m/s

Part a)

Horizontal displacement in 1.03 s

x = v_x t

x = (15.3)(1.03)

x = 15.76 m

Part b)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(1.03) - 4.9(1.03)^2

y = 7.94 m

Part c)

Horizontal displacement in 1.71 s

x = v_x t

x = (15.3)(1.71)

x = 26.16 m

Part d)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(1.71) - 4.9(1.71)^2

y = 7.49 m

Part e)

Horizontal displacement in 5.44 s

x = v_x t

x = (15.3)(5.44)

x = 83.23 m

Part f)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(5.44) - 4.9(5.44)^2

y = -75.6 m

6 0
3 years ago
Write the equation of a function h(t) that represents the amount of heat in joules required to heat the bar to a temperature of
bearhunter [10]
The initial temperature of the bar is 25. To get to the t temperature you need to add (t-25) degrees Celsius.

for 1 degree................... 7 Joules
      y given degree........  p Joules

p=7y

In our case y=(t-25) .

h(t) = 7(t-25) which is the final answer.

8 0
2 years ago
I will give brainliest if right
e-lub [12.9K]

Answer:

Prokaryotic Cells are cells that lack Cell Nucleus so the answer is bacteria

5 0
3 years ago
Read 2 more answers
Convert 0.0375 kg to g
leonid [27]

Answer: 37.5 g

Explanation: you multiply 0.0375 by 1000 which equals 37.5

8 0
3 years ago
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al aplicar una fuerza de 2 N sobre un muelle este se alarga 4cm.¿cuanto se alargara si la fuerza es el triple?¿que fuerza tendri
3241004551 [841]

1) 12 cm

2) 3 N

Explanation:

1)

The relationship between force and elongation in a spring is given by Hooke's law:

F=kx

where

F is the force applied

k is the spring constant

x is the elongation

For the spring in this problem, at the beginning we have:

F=2 N

x=4 cm

So the spring constant is

k=\frac{F}{x}=\frac{2N}{4 cm}=0.5 N/cm

Later, the force is tripled, so the new force is

F'=3F=3(2)=6 N

Therefore, the new elongation is

x'=\frac{F'}{k}=\frac{6}{0.5}=12 cm

2)

In this second problem, we know that the elongation of the spring now is

x=6 cm

From part a), we know that the spring constant is

k=0.5 N/cm

Therefore, we can use the following equation to find the force:

F=kx

And substituting k and x, we find:

F=(0.5)(6)=3 N

So, the force to produce an elongation of 6 cm must be 3 N.

6 0
3 years ago
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