If the distance between two objects is doubled, then the gravitational forces between them become (1/2)² = 1/4 of the original gravitational forces.
If the magnitude of those forces was 10 Newtons before the move then they're 2.5 Newtons after it.
I changed the wording of the discussion to plural, because the wording in the question is misleading. It shouldn't say "Object A attracts Object B" and then let it go at that. Gravitational forces ALWAYS occur in equal pairs. If Object B feels a pull of 10 Newtons toward Object A, then Object A feels a pull of 10 Newtons toward Object B.
The masses don't even matter. Gravity is always there equally in both directions. Your weight on Earth is equal to the Earth's weight on you !
For this case, the first thing you should do is write the kinematic motion equation of the block.
We have then:
vf = vo + a * t
Where,
vf: Final speed.
vo: Initial speed.
a: acceleration.
t: time.
Substituting the values:
(16) = (0) + a * (16)
Clearing the acceleration:
a = 16/16 = 1m / s ^ 2
Note: the other data for this case are not used in this problem.
answer:
The acceleration of the box is 1m / s ^ 2
La velocidad del buzo es de 7.04 m/s, 8.84 m/s y 2.27 m/s respectivamente.
<h3 /><h3>Velocidad
</h3>
La velocidad es la relación entre la distancia total recorrida y el tiempo total empleado. Está dado por:
Velocidad = distancia/tiempo
Para 10m de altura:
- Velocidad = 10 m/1.42 s = 7.04 m/s
Para 3m de altura:
- Velocidad = 3 m/0.78 s = 3.84 m/s
Para 1m de altura:
- Velocidad = 1 m/0.44 s = 2.27 m/s
La velocidad del buzo es de 7.04 m/s, 8.84 m/s y 2.27 m/s respectivamente.
Obtenga más información sobre la velocidad en: brainly.com/question/4931057
Answer:
The kinetic energy of the phone would increase. The gravitational potential energy of the phone would decrease.
Explanation:
The kinetic energy 
of an object is proportional to the square of the speed of that object. If air resistance is negligible, the phone would accelerate under gravitational pull and speed up. Hence, the kinetic energy of the phone would increase.
The gravitational field near the surface of the earth is approximately constant. Hence, the gravitational potential energy 
of the phone would be proportional to its height. As the phone approaches the ground, the height of the phone becomes lower and the gravitational potential energy of the phone would decrease.
A negative object so it takes in the charged object and nothing will happen until something else would touch it I think
