Answer:
The melting point of a substance referst to the temperature at which it changes state from solid to liquid. Therefore, the statement "The melting point of glycerine is 13 degree celsius" means that when the temperature at which glycerine is subjected is equal or higher than 13 degree celsius, it changes state from solid to liquid.
For example, the melting point of water is 0 °C. It means that when the temperature is higher than 0°C water goes from solid (Ice) to liquid. We all have seen that, right? ✔️
Electrical energy is your answer.
Answer:
(a) 2.5 cm
(b) Yes
Solution:
As per the question:
Mass of Uranium-235 ion, m =
Mass of Uranium- 238, m' =
Velocity, v =
Magnetic field, B = 0.250 T
q = 3e
Now,
To calculate the path separation while traversing a semi-circle:
The radius of the ion in a magnetic field is given by:
R =
Now,
By putting suitable values in the above eqn:
(b) Since the order of the distance is in cm, thus clearly this distance is sufficiently large enough in practical for the separation of the two uranium isotopes.
Answer:
a)η = 0.088
b) η = 0.5
Explanation:
a) The attached figure shows the P-V diagram for the process described in the exercise. According to that figure, the work during process 1-2 is equal to:
W(1-2) = -n*R*T1*ln(vi/vf) = -n*R*T1*ln(V/(V/2)) = -n*R*T1*ln(2)
the work during process 2-3 is equal to:
W(2-3) = nR*(T2-T1)
The work done during the 3-1 process equals zero, because the volume is constant. The specific heat for the molar specific heat equals:
cp = 7*R/2, where R is gas constant.
Qin = n*cp*(T2-T1) = 7*n*R/2*(T2-T1)
the efficiency of the cycle is equal to:
η = (W(1-2) + W(2,3))/Qin = (-n*R*T1*ln2 + n*R*(T2-T1))/(7*n*R/2*(T2-T1) = (2/7)*(1-(ln2/((T2/T1)-1)))
if we write the expression between volume and temperature, we have:
T2/T1 = v1/v2
T2/T1 = v/(v/2))
T2/T1 = 2
η = (2/7)*(1-(ln2/(2-1))) = 0.088
b)
The equation for efficiency of Carnot will be equal to:
η = 1-(T1/T2) = 1 - (1/2) = 0.5
<span>Most objects tend to contain the same numbers of positive and negative charge because this is the most stable situation. In fact, if an object has an excess of positive charge, it tends to attract an equal number of negative charges to balance this effect and restore neutrality: the attracted negative charges combine with the excess of positive charges, leaving the object electrically neutral.</span>