Answer:
The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.
The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds
im not sure about most of this but ill try to help
so there are three formulas you need to know first: the formula for rate distance and time.
to find distance:
distance = rate * time
to find time:
time = distance / rate
and to find rate (which is what we need)
rate = distance / time
now we just use our formula and plug in the numbers
rate = distance * time
rate = 160 / 2 = 80
so our rate is 80. thats all i know i have no idea about the rest but i always use these messurments. im sure you can google most of it to get other formulas and calculators though. sorry i couldnt help much! good luck :D
Answer:
These regions are known as compressions and rarefactions respectively. The compressions are regions of high air pressure while the rarefactions are regions of low air pressure.
Explanation:
Answer:
Answered
Explanation:
v= 1 m/s
A= 1 m^2
m= 100 kg
y= 1 mm
μ = ?
ζ= viscosity of SAE 20 crankcase oil of 15° C= 0.3075 N sec/m^2
forces acting on the block are
F_s ← ↓ →F_f
mg
N= mg
F_s= shear force = ζAv/y F_f= friction force = μN
now in x- direction F_s= F_f
ζAv/y = μN
0.3075×1×1×1/1×10^{-3} = μ×100
⇒μ=0.313 (coefficient of sliding friction for the block)
Now, as the velocity is increased shear force also increases and due to this frictional force also increases.
Now, to compensate this frictional force friction coefficient must increase
as v∝μ