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Shalnov [3]
3 years ago
5

All of the alkali metals, Group 1, have one valence electron. Which of these would represent the oxidation number of the alkali

metals such as lithium and sodium? A) -7 B) -1 C) +1 D) +7
Physics
2 answers:
melamori03 [73]3 years ago
8 0
The elements found in the Group 1, or the Alkali Metal Group, have electronic configurations that end in s^{1}.This means that they have 1 electron readily available to release in order to achieve a stable state. 

When these atoms release the valence electron, they will achieve a stable state. For example, Lithium's stable state will be Li^{+} and Sodium will be Na^{+}. 

The oxidation state will then be +1. 

The answer is C. 


Alinara [238K]3 years ago
8 0

Answer:

c

Explanation:

i did the usa test prep

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A patient is administered 20 mg of iodine-131. How much of this isotope will remain in the body after 40 days if the half-life f
igor_vitrenko [27]

The formula for half-life is:

A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h}}

Where A is the amount of iodine-131 initially and after 40 days, t is time, h is half-life of the isotope.  Let's plug in our values to the equation:

A_{final}=20(\frac{1}{2})^{\frac{40}{8}=0.625g

Therefore, the patient has 0.625 grams of iodine-131 after 40 days.

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3 years ago
if the distance of separation begin two objects is doubled, is the gravitational force between the objects increased or decrease
SashulF [63]

Answer:

force is decreased by a factor of 4.

Explanation:

According to the Newton's law of gravitation, the force of gravitation between the two object is inversely proportional to the square of distance between them. Now the distance is doubled, so the force between the two objects becomes one forth.

Force is decreased by a factor or 4.

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3 years ago
Mike shoots a large marble (Marble A, mass: 0.05 kg) at a smaller marble (Marble B, mass: 0.03 kg) that is sitting still. Marble
SpyIntel [72]

<u>Answer</u>

1 1/3 m/s


<u>Explanation</u>

The momentum before collision and after collision is always conserved.

m₁v₁ = m₂v₂

(0.05×0.6) + (0.03×0) = (0.03 × v) + (0.05 × -0.2)

0.03 + 0 = 0.03v - 0.01

0.03v = 0.03+0.01

0.03v = 0.04

v = 0.04/0.03

  = 4/3

   = 1 1/3 m/s

7 0
4 years ago
Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about the amounts o
likoan [24]

Answer:

1) At the highest point of the building.

2) The same amount of energy.

3) The kinetic energy is the greatest.

4) Potential energy = 784.8[J]

5) True

Explanation:

Question 1

The moment when it has more potential energy is when the ball is at the highest point in the building, that is when the ball is at a height of 40 meters from the ground. It is taken as a point of reference of potential energy, the level of the soil, at this point of reference the potential energy is zero.

E_{p} = m*g*h\\E_{p} = 2*9.81*40\\E_{p} = 784.8[J]

Question 2)

The potential energy as the ball falls becomes kinetic energy, in order to be able to check this question we can calculate both energies with the input data.

E_{p}=m*g*h\\ E_{p} = 2*9.81*20\\ E_{p} = 392.4[J]\\

And the kinetic energy will be:

E_{k}=0.5*m*v^{2}\\  where:\\v =  velocity = 19.8[m/s]\\E_{k}=0.5*2*(19.8)^{2}\\  E_{k}=392.04[J]

Therefore it is the ball has the same potential energy and kinetic energy as it is half way through its fall.

Question 3)

As the ball drops all potential energy is transformed into kinetic energy, therefore being close to the ground, the ball will have its maximum kinetic energy.

E_{k}=E_{p}=m*g*h = 2*9.81*40\\  E_{k} = 784.8[J]\\ E_{k} = 0.5*2*(28)^{2}\\ E_{k} = 784 [J]

Question 4)

It can be easily calculated using the following equation

E_{p} =m*g*h\\E_{p}=2*9.81*40\\E_{p} =784.8[J]

Question 5)

True

The potential energy at 20[m] is:

E_{p}=2*9.81*20\\ E_{p}= 392.4[J]\\The kinetic energy is:\\E_{k}=0.5*2*(19.8)^{2} \\E_{k}=392[J]

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