This should include distances. Displacement is the shortest distance from point A to point B. Distance is the total length of travel. For an example I have included a simple map.
Displacement would not be an accurate representation of the driving instructions because it would not tell the total length of travel. Basically, the driver would be going through buildings if you told them displacement. Directions would tell them the roads traveled.
Answer: a) 110 *10^-6 m (110 μm); b) 82.86*10^-6 m (82.86 μm).
Explanation: In order to explain this problem we have to consider the expresion for the dark fringes in a difraction pattern for a single narrow slit. It is given by:
a*sin (θ)= m*λ where a is the slit width. θ is the angle corresponding the m dark fringe from the central axis. λ is the wavelength of the incident light.
Then we have m=10 and θ=6° so;
a=10*1152*10^-9/Sin(6°)=110 *10^-6 m
Finally if the whole system is inmmersed in water (n=1.33), we have to add the refractive index in the path difference then: a*n*sin(θ)
a*n*sin (θ)= m*λ then
a= m*λ/(n*sin (θ))=10*1152*10^-9/1.33*Sin(6°)= 82.86* 10^-6 m
Answer:
option (a)
Explanation:
Maintaining distance while driving in traffic can avoid the chances of an accident.
When the driver is behind you is trying to pass you to avoid the collision you should maintain a distance greater than 3 sec.
Hence, option (a) is correct.
Yes, that's a true statement.