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vodka [1.7K]
3 years ago
6

Planet Tatoone is about 1.7 AU from its Sun. Approximately how long will it take for light to travel from the Sun to Tatoone in

minutes? Use 3 × 108 m/s for the speed of light.
Physics
1 answer:
Radda [10]3 years ago
8 0

Answer:

The value is   t =  14.129 \  minutes    

Explanation:

From the question we are told that

  The distance of planet Tatoone is  d =  1.7 \ AU  =  1.7 *1.496* 10^{11}=2.543*10^{11} \ m

   The  speed of light is  c =  3.0*10^{8} \  m/  s

Generally the time taken is mathematically represented as

     t =  \frac{d}{c}

=> t =  \frac{2.543*10^{11}}{3.0*10^{8} }

=>    t =  847.7 \  s

Now converting to minutes

       t =  \frac{847.7}{60}

   =>     t =  14.129 \  minutes    

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Answer:

Explanation:

work done by applied force

= force x displacement

= 7.6 x 15 m

= 114 J .

6 0
3 years ago
A block attached to a spring with an unknown spring constant oscillates with a period of 2.0 s. What is the period if
Zigmanuir [339]

Answer:

a) If the mass is doubled, then the period is increased by \sqrt{2}. Hence, the period of the system is 2.828 seconds.

b) If the mass is halved, then the period is reduced by \frac{\sqrt{2}}{2}. Hence, the period of the system is 1.414 seconds.

c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.

d) If the spring constant is doubled, then the period is reduced by \frac{\sqrt{2}}{2}. Hence, the period of the system is 1.414 seconds.

Explanation:

The statement is incomplete. We proceed to present the complete statement: <em>A block attached to a spring with unknown spring constant oscillates with a period of 2.00 s. What is the period if </em><em>a. </em><em>The mass is doubled? </em><em>b.</em><em> The mass is halved? </em><em>c.</em><em> The amplitude is doubled? </em><em>d.</em><em> The spring constant is doubled? </em>

We have a block-spring system, whose angular frequency (\omega) is defined by the following formula:

\omega = \sqrt{\frac{k}{m} } (1)

Where:

k - Spring constant, measured in newtons per meter.

m - Mass, measured in kilograms.

And the period (T), measured in seconds, is determined by the following expression:

T = \frac{2\pi}{\omega} (2)

By applying (1) in (2), we get the following formula:

T = 2\pi\cdot \sqrt{\frac{m}{k} }

a) If the mass is doubled, then the period is increased by \sqrt{2}. Hence, the period of the system is 2.828 seconds.

b) If the mass is halved, then the period is reduced by \frac{\sqrt{2}}{2}. Hence, the period of the system is 1.414 seconds.

c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.

d) If the spring constant is doubled, then the period is reduced by \frac{\sqrt{2}}{2}. Hence, the period of the system is 1.414 seconds.

8 0
3 years ago
A car with a mass of 600 kg is traveling at a velocity of 10 m/s. How much kinetic energy does it have?
Viefleur [7K]

Answer:

KE = 30,000 J

Explanation:

KE = \frac{1}{2} mv²

KE = \frac{1}{2} (600)(10)²

KE = \frac{1}{2} (600)(100)

KE = \frac{1}{2} (60000)

KE = 30,000 J

5 0
3 years ago
If a car changes its velocity from 32 km/hr to 54 km/hr in 8.0 seconds, what is its acceleration?
Stella [2.4K]
Use the equation for the acceleration
A = final velocity - initial velocity divided by time final - time initial
A= 54 - 32 / 8 - 0
A= 22 / 8 
A= 2.75 m/s^2 
Hope this helps!
3 0
3 years ago
Read 2 more answers
What is the acceleration of the box?
worty [1.4K]

Answer:

a=4,32m/s^2

Explanation:

Fnet = F1 - F2

= 12-1.2

= 10.8N

m=2.5kg

Fnet =ma

10.8=2.5a then divide both sides by 2.5 to get acceleration

8 0
3 years ago
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