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3 years ago

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3h2(g)+o3(g) 3h20(g) arrow after the o3(g)whats the overall enthalpy?

1 answer:

Dmitry_Shevchenko [17]3 years ago

8 0

The overall enthalpy of reaction will be calculated from enthalpy of formation of products and reactants.

DeltaHrxn = [Sum of enthalpy of formation of products] - [sum of enthalpy of formation of reactants]

DeltaHrxn = 3 X deltaHf (H2O) - [ 3 X DeltaH (H2) + DeltaH (O3)]

DeltaHrxn = 3 X (--242) - [ 0 + 143] = -869 kJ / mole

We can also calculate the enthalpy of reaction from bond energies

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Calculate the energy (in kJ) required to heat 10.1 g of liquid water from 55 oC to 100 oC and change it to steam at 100 oC. The

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Answer:

$\large\boxed{\large\boxed{24.6kJ}}$

Explanation:

<u>1. Energy to heat the liquid water from 55ºC to 100ºC</u>

$Q=m\times C\times \Delta T$

m = 10.1g

C = 4.18g/JºC

ΔT = 100ºC - 55ºC = 45ºC

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<u>2. Energy to change the liquid to steam at 100ºC</u>

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<u>3. Total energy</u>

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