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sveta [45]
4 years ago
6

Phenol red is an indicator that changes color over a range from ph=6.4 to ph=8.0. what is ka of phenol red?

Chemistry
1 answer:
patriot [66]4 years ago
7 0
First, we will get the average pH of the two given values:
average pH = (6.4+8) / (2) = 7.2
At this average pH, the concentration of the acid from the phenol red is equal to the concentration of the base.
pH = 7.2
[H+] = 10^(-7.2) = 6.3 * 10^-8

Phenol red has the general formula HA, this gives us:
HA <.......> H+ + A- 
At pH = 7.2, [H+] = [A-]
<span>Ka = [H+][A-]/ [HA]
</span>Ka = [H+] = <span>6.3 x 10^-8</span>

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4 years ago
Calculate the molar solubility of calcium hydroxide in a solution buffered at each ph.
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Dissociation reaction of calcium hydroxide can be represented as follows:

<span>Ca(OH)2 (s)      ⇄         Ca2+(aq) +         2OH-(aq)
</span>
The solubility product of Ca(OH)2 is mathematically expressed as 
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Given: Ksp = <span>4.68 x 10-6

Now, we know that for aqueous system, pH + pOH = 14
and pOH = -log(OH-)
Thus, [OH-] = </span><span>10^(pH - 14)

</span>∴ Ksp = [Ca2+] [10^(pH - 14)]^2 =  [Ca2+] [10^(2.pH - 28)]
∴ [Ca2+]    =    Ksp/10^(2.pH - 28)
                  =   Ksp 10^(28 - 2.pH)

Now, at pH = 4
[Ca2+] = Ksp 10^(28 - 2.pH)
            = (4.68 x 10-6) 10^(28 - 2X4)
            = 4.68 X 10^14 mol/dm3

At pH = 7,
[Ca2+] = Ksp 10^(28 - 2.pH)
            = (4.68 x 10-6) 10^(28 - 2X7)
            = 4.68 X 10^8 mol/dm3
At pH = 9
[Ca2+] = Ksp 10^(28 - 2.pH)
            = (4.68 x 10-6) 10^(28 - 2X9)
            = 4.68 X 10^4 mol/dm3

Answer:
Following is molar solubility of calcium hydroxide at different pH
at pH 4 = 4.68 X 10^14 mol/dm3
at pH 7 = 4.68 X 10^8 mol/dm3
at pH 9 = 4.68 X 10^4 mol/dm3


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